Answer:
See below in bold.
Step-by-step explanation:
y = -x^2 - 2x - 5
Convert to vertex form:
y = -(x^2 + 2x) - 5
y = - [(x + 1)^2 - 1] - 5
y = -(x + 1)^2 + 1 - 5
y = -(x + 1)^2 - 4
So the vertex of the graph is at (-1 , -4) and it is a maximum because the coefficient of x^2 is negative.
So the range is all values of f(x) up to and including -4.
In interval notation this is (-∞, -4].
$16
4k(2k² - 5k - 4) + 5(2k² - 5k - 4)
8k³ - 20k² - 16k + 10k² -25k - 20
8k³ - 10k² - 41k - 20
Thus its G
