What is the RANGE of the following graph? y=-x2- 2x - 5 2

Mathematics

2 answers:

MA_775_DIABLO [31]2 years ago

7 0

Answer:

See below in bold.

Step-by-step explanation:

y = -x^2 - 2x - 5

Convert to vertex form:

y = -(x^2 + 2x) - 5

y = - [(x + 1)^2 - 1] - 5

y = -(x + 1)^2 + 1 - 5

y = -(x + 1)^2 - 4

So the vertex of the graph is at (-1 , -4) and it is a maximum because the coefficient of x^2 is negative.

So the range is all values of f(x) up to and including -4.

In interval notation this is (-∞, -4].

yan [13]2 years ago

6 0

The range would be the number-

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