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o-na [289]
2 years ago
6

A 748 L hot air balloon sits on a table at 26.7oC. If the balloon is heated to 48.3oC, what is the new volume?

Chemistry
1 answer:
Naddik [55]2 years ago
3 0

The new volume of the hot air balloon is 801.9L.

As the temperature of the hot air balloon on the table is increased, the its volume also increases.

<h3>Charle's law</h3>

Charle's law states that the volume of an ideal gas is directly proportional to the absolute temperature provided pressure is kept at constant.

It is expressed as;

V₁/T₁ = V₂/T₂

Given the data in the question;

  • Initial volume V₁ = 748L
  • Initial temperature T₁ = 26.7°C = 299.85K
  • Final temperature T₂ = 48.3°C = 321.45K
  • Final volume V₂ = ?

To calculate the new volume we subtsitute our given values into the expression above.

V₁T₂ = V₂T₁

V₂ = V₁T₂ / T₁

V₂ = ( 748L × 321.45K ) / 299.85K

V₂ = 240444.6LK / 299.85K

V₂ = 801.9L

The new volume of the hot air balloon is 801.9L.

As the temperature of the hot air balloon on the table is increased, the its volume also increases.

Learn more about Charle's law here: brainly.com/question/21184611

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Ammonia will decompose into nitrogen and hydrogen at high temperature. An industrial chemist studying this reaction fills a 5.0L
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Answer:

Kp = 7.4727

Explanation:

Let's write the balanced equilibrium reaction:

2NH₃ <-------> N₂ + 3H₂     Kp = ??

Now, if we want to calculate the Kp, we need to write an ICE chart with this reaction, which is the following:

         2NH₃ <-------> N₂ + 3H₂  

I.         4,5                 0        0

C.       -2x                +x     +3x

E.        4,5-2x            x       3x

According to this chart, the Kp expression should be:

Kp = (PH₂)³ * (PN₂) / (PNH₃)²   (1)

The value of x, we already know it because the problem states that the amount of nitrogen gas is 1.1 atm, so replacing this value into (1) we have:

Kp = (3*1.1)³ * (1.1) / (4.5 - (2 * 1.1))²

Kp = 39.5307 / 5.29

<h2>Kp = 7.4727</h2>

Hope this helps

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What is a giant ball of glowing gas that generates energy by nuclear fusion reaction?​
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9. How long will it take 120 grams of Strontium-90 to decay to 7.5 grams?<br>with steps pls​
ryzh [129]

Answer:

116 years

Explanation:

To solve this, we will use the half life equation;

A(t) = A_o(½)^(t/t_½)

Where;

A(t) is the amount of strontium left after t years;

A_o is the initial quantity of strontium that will undergo decay;

t_½ is the half-life of strontium

t is the time it will take to decay

We are given;

A(t) = 7.5 g

A_o = 120 g

From online values, half life of strontium-90 is 29 years. Thus, t_½ = 29

Thus;

7.5 = 120 × ½^(t/29)

Divide both sides by 120 to get;

7.5/120 = ½^(t/29)

0.0625 = ½^(t/29)

In 0.0625 = (t/29) In ½

-2.772589 = (t/29) × (-0.693147)

(t/29) = -2.772589/(-0.693147)

t/29 = 4

t = 29 × 4

t = 116 years

5 0
3 years ago
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