Question

A 748 L hot air balloon sits on a table at 26.7oC. If the balloon is heated to 48.3oC, what is the new volume?

Answer 1

The new volume of the hot air balloon is 801.9L.

As the temperature of the hot air balloon on the table is increased, the its volume also increases.

Charle's law

Charle's law states that the volume of an ideal gas is directly proportional to the absolute temperature provided pressure is kept at constant.

It is expressed as;

V₁/T₁ = V₂/T₂

Given the data in the question;

• Initial volume V₁ = 748L

• Initial temperature T₁ = 26.7°C = 299.85K

• Final temperature T₂ = 48.3°C = 321.45K

• Final volume V₂ = ?

To calculate the new volume we subtsitute our given values into the expression above.

V₁T₂ = V₂T₁

V₂ = V₁T₂ / T₁

V₂ = ( 748L × 321.45K ) / 299.85K

V₂ = 240444.6LK / 299.85K

V₂ = 801.9L

The new volume of the hot air balloon is 801.9L.

As the temperature of the hot air balloon on the table is increased, the its volume also increases.

Learn more about Charle's law here: brainly.com/question/21184611