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matrenka [14]
3 years ago
13

What do these two changes have in common? Shaking up salad dressing. Adding dish soap to water in a sink

Chemistry
1 answer:
Ghella [55]3 years ago
4 0
I think it’s a maybe hope this helps
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Which physical property is being used to separate the mixtures in each of the following cases?
kirill115 [55]

I think that this is

6 0
3 years ago
In which of the following reactions will Kc = Kp? Group of answer choices N2(g) + 3 H2(g) 2 NH3(g) N2O4(g) 2NO2(g) CO(g) + 2 H2(
Artist 52 [7]

Answer:

H₂(g) +I₂(g) ⟶ 2HI(g)

Explanation:

Kc =Kₚ when the number of moles of gaseous products equals the number of moles of gaseous reactants.

The HI reaction has two moles of gas on each side of the reaction arrow.

K = (Products)ⁿ/(Reactants)ⁿ = (Products/Reactants)ⁿ

Thus, if n is the same for products and reactants, you will get the same number whether you use concentrations or pressures, and Kc = Kₚ

8 0
3 years ago
True or False?<br><br> Density of ocean water is not affected by salinity (salt content).
Nastasia [14]

Answer:

false

Explanation:

8 0
3 years ago
Read 2 more answers
Which equation, in which k is a constant, represents an inverse proportion between the variables? V = T/k F = –kx2 PV = k y = kx
Alona [7]

The inverse proportion is PV = k

We can write the equation as <em>P</em> = k/<em>V</em> or <em>P</em> ∝ 1/<em>V</em>. Thus, <em>P</em> and <em>V</em> are <em>inversely related</em>.

We can rewrite <em>V</em>= T/k as <em>V</em> = k<em>T</em> or <em>V</em> ∝ <em>T</em>. Thus,<em> V</em> is <em>directly proportiona</em>l to <em>T</em> .

<em>F</em> = -k<em>x</em>² is <em>neither a direct nor an invers</em>e relation.

<em>y</em> = k<em>x</em> – 8 is a linear relation, but it is <em>not a direct proportion</em> because of the “-8” term.

5 0
3 years ago
7. How many moles of argon are there in 20.0 L, at 25 degrees Celsius and 96.8 kPa?
suter [353]
<h3>Answer:</h3>

              0.8133 mol

<h3>Solution:</h3>

Data Given:

                 Moles  =  n  =  ??

                 Temperature  =  T  =  25 °C + 273.15  =  298.15 K

                  Pressure  =  P  =  96.8 kPa  =  0.955 atm

                  Volume  =  V  =  20.0 L

Formula Used:

Let's assume that the Argon gas is acting as an Ideal gas, then according to Ideal Gas Equation,

                  P V  =  n R T

where;  R  =  Universal Gas Constant  =  0.082057 atm.L.mol⁻¹.K⁻¹

Solving Equation for n,

                  n  =  P V / R T

Putting Values,

                  n  =  (0.955 atm × 20.0 L) ÷ (0.082057 atm.L.mol⁻¹.K⁻¹ × 298.15 K)

                 n  =  0.8133 mol

4 0
3 years ago
Read 2 more answers
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