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How many liters are in a .00813M solution that contains 1.55 g of KBr?

Sloan [31]

Answer:

1.602 L (or) 1602 mL

Explanation:

Molarity is the amount of solute dissolved per unit volume of solution. It is expressed as,

Molarity = Moles / Volume of Solution ----- (1)

Rearranging above equation for volume,

Volume of solution = Moles / Molarity -------(2)

Data Given;

Molarity = 0.00813 mol.L⁻¹

Mass = 1.55 g

First calculate Moles for given mass as,

Moles = Mass / M.mass

Moles = 1.55 g / 119.002 g.mol⁻¹

Moles = 0.0130 mol

Now, putting value of Moles and Molarity in eq. 2,

Volume of solution = 0.0130 mol / 0.00813 mol.L⁻¹

Volume of solution = 1.60 L

or,

Volume of solution = 1602 mL

5 0

3 years ago

Lewis structures for the perchlorate ion (ClO4−) can be drawn with all single bonds or with one, two, or three double bonds. Dra

Vanyuwa [196]

Answer:

The most important resonance structure is 4 (attached picture). Its bon order is $\frac{7}{4}$ or $1\frac{3}{4}$ .

Explanation:

A picture with 4 forms of the perchlorate structure is attached. The first structure has simple bonds. The second structure contains a double bond, the third structure has two double bonds and the fourth structure has three double bonds.

Formal charge = group number of the periodic table - number of bonds (number of bonding electrons / 2) - number of non-shared electrons (lone pairs)

The formal charges in the first structure is +3 in chlorine and -1 in oxygen.

The formal charges in the second structure is +2 in chlorine, -1 in oxygen and 0 in the double bond oxygen.

The formal charges in the third structure is +1 in chlorine, -1 in the single bond oxygens and 0 in the double bond oxygens.

The formal charges in the fourth structure is 0 in chlorine, -1 in the single bond oxygen and 0 in the double bond oxygens.

The most important resonance structure is given by:

Most atoms have 0 formal charge.

Lowest magnitude of formal charges.

If there is a negative formal charge, it's on the most electronegative atom.

Hence, the fourth structure is the mosr important.

The bond order of the structure is:

Total number of bonds: 7

Total number of bond groups: 4

Bond order= $\frac{7}{4} =1\frac{3}{4}$

5 0

3 years ago

1. When an acid reacts with a base, what compounds are formed? (1 point) a salt only water only metal oxides only a salt and wat

scoundrel [369]

Answer: 1) only a salt and water

An acid and base reacts together to undergo neutralization to form salt and water.

$HCl+NaOH\rightarrow NaCl+H_2O$

where HCl is an acid and NaOH is a base to form salt (NaCl) and water $(H_2O)$ .

Answer: 2) The formula of the hydrogen ion is often written as $H^+$ .

All acids dissociate in water to give $H^+$ ions.

Answer: 3) Arrhenius acids are substances that ionizes to yield protons in aqueous solution.

$HCl\rightarrow H^++Cl^-$

Arrhenius bases are substance that ionizes to yield hydroxide ions in aqueous solution.

$NaOH\rightarrow Na^++OH^-$

Answer: 4) A conjugate acid base pair transfers hydrogen ion.

$CH_3COO^-+H_2O\rightarrow CH_3COOH+H_3O^+$

Here $CH_3COO^-$ accepts a proton and thus act as a base and the corresponding $CH_3COOH$ is its conjugate acid.

Answer: 5) Bronsted Lowry acid is a substance that donates protons. Bronsted Lowry base is a substance that accepts protons.

$NH_4^+$ and $NH_3$

$NH_3+H^+\rightarrow NH_4^+$

$NH_3$ is a acid which accepts proton and thus acts as base to form conjugate acid $NH_4^+$ .

4 0

2 years ago

Read 2 more answers

In an experiment, what is the purpose of the control group?

Burka [1]

A control group is the comparison group that helps to "make sure your experiment works." A control group is separated from the rest of the experiment and nothing happens to it kinda like a controlled variable. Controlled variables are the variables in a experiment that remains the same for example a temperature, time, type of products, etc..

Hope this helps!

7 0

3 years ago

Read 2 more answers

Help me please) attached the screen below. Thanks

Vitek1552 [10]

Answer:

1) d = 2.4 g/cm³

2) m = 25 g

3) v = 126.7 cm³

Explanation:

Given data:

Mass of material = 24 g

Volume of material = 10 cm³

Density of material = ?

Solution:

Formula:

d = m/v

by putting value,

d = 24 g / 10 cm³

d = 2.4 g/cm³

2) Given data:

Density of material = 5 g/cm³

Volume of material = 5 cm³

Mass of material = ?

Solution:

Formula:

d = m/v

5 g/cm³ = m / 5 cm³

m = 5 g/cm³×5 cm³

m = 25 g

3)Given data:

Density of material = 3 g/cm³

Mass of material = 380 g

Volume of material = ?

Solution:

Formula:

d = m/v

3 g/cm³ = 380 g / v

v = 380 g /3 g/cm³

v = 126.7 cm³

7 0

3 years ago