If a material mixes readily with water it is describe as HYDROPHILIC. Hydrophilic substances are water loving molecules, there reaction with water is favorable in term of thermodynamics. This type of substance are usually charged and often have ability to get involve in hydrogen bonding.
I think the answer is D.
The SLM states for long term productive potential, the other three are clear on how this would affect the future in these areas, but D pertains to the now of tilling and mulching the ground. Though it looks like all the statements are true, D doesn’t it with the UN’s SLM.
Hope this help!
They are unicellular organisms with flagella.
They do not have a cell wall.
They have a thick outer covering, known as pellicle, that is composed of protein and gives them both strength and flexibility.
They are eukaryotes.
Explanation:
Relation between
and
is as follows.
![K_{p} = K_{c} [RT]^{\Delta n}](https://tex.z-dn.net/?f=K_%7Bp%7D%20%3D%20K_%7Bc%7D%20%5BRT%5D%5E%7B%5CDelta%20n%7D)
Given, temperature =
= (830 + 273) K = 1103 K
R = 8.314 J/mol K
= 1 - 0 = 1
Now, putting the given values into the above formula as follows.
![K_{p} = K_{c} [RT]^{\Delta n}](https://tex.z-dn.net/?f=K_%7Bp%7D%20%3D%20K_%7Bc%7D%20%5BRT%5D%5E%7B%5CDelta%20n%7D)
0.5 = ![K_{c} \times (8.314 \times 1103)^{1}](https://tex.z-dn.net/?f=K_%7Bc%7D%20%5Ctimes%20%288.314%20%5Ctimes%201103%29%5E%7B1%7D)
![K_{c} = 5.452 \times 10^{-3}](https://tex.z-dn.net/?f=K_%7Bc%7D%20%3D%205.452%20%5Ctimes%2010%5E%7B-3%7D)
ICE table for the given reaction will be as follows.
![CaCO_{3}(s) \rightleftharpoons CaO(s) + CO_{2}(g)](https://tex.z-dn.net/?f=CaCO_%7B3%7D%28s%29%20%5Crightleftharpoons%20CaO%28s%29%20%2B%20CO_%7B2%7D%28g%29)
Initial: c - -
Equilibrium: (c - x) x x
= ![[CO_{2}]](https://tex.z-dn.net/?f=%5BCO_%7B2%7D%5D)
= x
Hence, same amount of CaO is produced.
Moles of CaO = ![5.452 \times 10^{-3}](https://tex.z-dn.net/?f=5.452%20%5Ctimes%2010%5E%7B-3%7D)
Mass of CaO = ![5.452 \times 10^{-3} \times 57 g/mol](https://tex.z-dn.net/?f=5.452%20%5Ctimes%2010%5E%7B-3%7D%20%5Ctimes%2057%20g%2Fmol)
= 0.310 g
Thus, we can conclude that 0.310 g of CaO produced when equilibrium is established.
Answer:
2.047 × 10^22 atoms.
Explanation:
To calculate the number of atoms (nA) in AlCl3, we first need to find the number of moles in the compound, AlCl3.
Molar mass of AlCl3 = 27 + 35.5(3)
= 27 + 106.5
= 133.5g/mol
Using mole = mass/molar mass
mole = 4.5/133.5
mole = 0.034moles
number of atoms in a substance (nA) = number of moles (n) × Avagadros number or constant (6.02 × 10^23 atoms)
nA of AlCl3 = 0.034 × 6.02 × 10^23
nA = 0.2047 × 10^23
nA = 2.047 × 10^22 atoms.