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adoni [48]
2 years ago
8

13-18 Express the quantity as a single logarithm. 13.

20z" id="TexFormula1" title="2 \ln x+3 \ln y-\ln z" alt="2 \ln x+3 \ln y-\ln z" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
r-ruslan [8.4K]2 years ago
5 0

2 \ln x+ 3 \ln y - \ln z\\\\=\ln x^2 + \ln y^3 - \ln z\\\\=\ln(x^2 y^3) - \ln z\\\\=\ln \left( \dfrac{x^2y^3}{z} \right)

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The answer is length AD is 3cm
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The perimeter of a rectangle sandpit is 40 meters. The length of the sandpit is 1 meter less than twice it's width. What are the
Aleks04 [339]

Answer:

L = 15, W = 8

Step-by-step explanation:

Perimeter = 2(L + W)

P = 40

L = 2W - 1

40 = 2((2W-1) + W)

40 = 4W - 2 + 2W

40 = 6W - 2

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Since L = 2W - 1

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4 years ago
Is this right? I don't get this whole page
Nonamiya [84]
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4 years ago
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To place an ad in the Harrisonburg newspaper it cost $100 for each 1/8 of a page used. How much would an advertisement cost if i
larisa86 [58]

Answer:

It would cost <u>$600</u> for an advertisement of  \frac{3}{4}  of a page.

Step-by-step explanation:

Given:

To place an ad in the Harrisonburg newspaper it cost $100 for each 1/8 of a page used.

Now, to find the cost of an advertisement 3/4 of a page.

So, to get the cost we use unitary method:

<em>If,  </em>\frac{1}{8}<em> of a page used cost = $100.</em>

<em>Then, 1 page used cost = </em>100\div \frac{1}{8}<em> = </em>\$800.<em />

<em>Thus,  </em>\frac{3}{4}<em>  of a page used cost</em> = 800\times \frac{3}{4} =\frac{2400}{4}=\$600.

Therefore, it would cost $600 for an advertisement of  \frac{3}{4}  of a page.

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3 years ago
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Vanyuwa [196]
The described situation represents a normal distribution.
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Therefore, the required percentage of the customers expected to get free gifts is 4.9%.
5 0
4 years ago
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