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myrzilka [38]
2 years ago
12

Miss Osborne enlarges a 4-inch by 6-inch photograph by 2.5x. What are the dimensions of the enlarged photograph?

Mathematics
1 answer:
Valentin [98]2 years ago
4 0

Answer:

<h2>C. 10in by 15in</h2>

Step-by-step explanation:

enlarging the photograph by 2.5x means multiplying all of the sides of the photograph 2.5 times

Then

the dimensions of the enlarged photograph are:

Width = 4 ×2.5 = 10

Length = 6 ×2.5 = 15

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zheka24 [161]

Answer:

Hello!

Let's simply divide our two numbers to find how many carriages we need.

22/4=5.5

The thing is, we cannot have 5.5 carriages. We can just have an extra carriage with only 2 people. This gives us 6 carriages.

Therefore, our answer is 6.

I hope this helps!

6 0
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1.08 x 10^-3 in standard form?
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Given congruent triangles name the corresponding sides and corresponding angles
Alborosie

Answer:

See explanation

Step-by-step explanation:

Given \triangle ABC\cong \triangle ADC

According to the order of the vertices,

  • side AB in triangle ABC (the first and the second vertices) is congruent to side AD in triangle ADC (the first and the second vertices);
  • side BC in triangle ABC (the second and the third vertices) is congruent to side DC in triangle ADC (the second and the third vertices);
  • side AC in triangle ABC (the first and the third vertices) is congruent to side AC in triangle ADC (the first and the third vertices);
  • angle BAC in triangle ABC is congruent to angle DAC in triangle ADC (the first vertex in each triangle is in the middle when naming the angles);
  • angle ABC in triangle ABC is congruent to angle ADC in triangle ADC (the second vertex in each triangle is in the middle when naming the angles);
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Solve each inequality 1 &lt; x -2
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7 0
3 years ago
Read 2 more answers
Inscribed circles on the arc; improvement answer is required in full.
e-lub [12.9K]

Answer:

The measure of an inscribed angle is half the measure of the intercepted arc

∠EFG creates Arc EDG

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A circle is 360°.

The remaining arc EFG is 360° - 230° = 130°

∠EDG is 1/2 of arc EFG so, 130° ÷ 2 = 65°

∠EDG = 65°

8 0
3 years ago
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