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melomori [17]
2 years ago
12

Please help me answer this question

Mathematics
1 answer:
bonufazy [111]2 years ago
5 0

Answer:

Step-by-step explanation:

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What is the volume of a cone with a height of 10.5 inches and a radius of 8 inches? cone v = 1 3 bh 1. rewrite the formula for t
bonufazy [111]

The volume of the cone that has a radius of 8 in. and a height of 10.5 in. is: 703.7 in.³

<h3>What is the Volume of a Cone?</h3>

Volume = 1/3πr²h

Given the parameters:

  • Height (h) = 10.5 in.
  • Radius (r) = 8 in.

Volume of the cone = 1/3πr²h = 1/3π(8²)(10.5)

Volume of the cone = 1/3π(64)(10.5)

Volume of the cone = 703.7 in.³

Learn more about volume of a cone on:

brainly.com/question/13677400

#SPJ1

3 0
2 years ago
Read 2 more answers
What was the average grade earned?
Anettt [7]
A 3 I guess or a B. idk....
5 0
3 years ago
Find the volume of the cone​
irina1246 [14]

Answer:

The volume of the cone is 12936 cubic mm.

Step-by-step explanation:

Given

Circumference of base = 132 mm

Height of the cone = 28 mm

Solution

Formula  of circumference = 2\pi r = 132 mm

\therefore\ r= \frac{132}{2 \pi } = 21 mm

Now volume of cone = \frac{1}{3} \times\pi \times r^{2} \times h

on substituting the value of r and h  we get ;

\frac{1}{3}\times\frac{22}{7} \times21\times21\times28= 12936\ mm

thus volume of cone is 12936  cubic mm.

4 0
3 years ago
Is the square root of 5 times the square root of 5 rational?
jeka57 [31]
 No 20.0000004 cannot be rational.
5 0
3 years ago
Yesterday Mike bought 2 gallons of regular gasoline and 3 gallons of premium gasoline at a gas station for $13.60 today he bough
larisa [96]

Answer:

Cost of 1 gallon of Regular gasoline is $2.45 and  Cost of 1 gallon of Premium gasoline is $2.90.

Step-by-step explanation:

Let the Cost of Regular gasoline be 'x'.

Let the Cost of Premium gasoline be 'y'.

Given:

Amount of regular gasoline bought yesterday = 2 gallons

Amount of premium gasoline bought yesterday = 3 gallons

Total Cost of yesterday = $13.60

Now we know that Total Cost of yesterday is equal to sum of Amount of regular gasoline bought yesterday multiplied by Cost of Regular gasoline and Amount of Premium gasoline bought yesterday multiplied by Cost of premium gasoline.

Framing in equation form we get;

2x+3y=13.60 \ \ \ \ equation\ 1

Also Given:

Amount of regular gasoline bought today = 3 gallons

Amount of premium gasoline bought Today = 4 gallons

Total Cost of Today = $18.95

Now we know that Total Cost of Today is equal to sum of Amount of regular gasoline bought Today multiplied by Cost of Regular gasoline and Amount of Premium gasoline bought Today multiplied by Cost of premium gasoline.

Framing in equation form we get;

3x+4y=18.95 \ \ \ \ equation\ 2

Now Multiplying equation 1 by 3 we get;

2x+3y=13.60\\\\3(2x+3y)=13.60\times3\\\\6x+9y= 40.80 \ \ \ \ \ equation\ 3

Now Multiplying equation 2 by 2 we get;

3x+4y=18.95\\\\2(3x+4y)=18.95\times2\\\\6x+8y= 37.90 \ \ \ \ \ \ equation\ 4

Subtracting equation 4 from equation 3 we get;

(6x+9y)- (6x+8y)= 40.80-37.90\\\\6x+9y-6x-8y= 2.9\\\\y=\$2.90

Substituting the value of y in equation 1 we get;

2x+3y=13.60\\\\2x+3\times2.90 =13.60\\\\2x+8.7=13.6\\\\2x=13.6-8.7\\\\2x=4.9\\\\x=\frac{4.9}{2} =\$2.45

Hence Cost of 1 gallon of Regular gasoline is $2.45 and  Cost of 1 gallon of Premium gasoline is $2.90.

4 0
3 years ago
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