The polynomial remainder theorem states that the remainder upon dividing a polynomial
by
is the same as the value of
, so to find
you need to find the remainder upon dividing
You have
..... | 2 ... 14 ... -58
-10 | ... -20 ... 60
--------------------------
..... | 2 ... -6 .... 2
So the quotient and remainder upon dividing is
with a remainder of 2, which means
.
Answer:
x > -15
Step-by-step explanation:
-x / 3 < 5
(-x / 3) * 3 < 5 * 3
-x < 15
x > -15 (Remember to flip the sign when multiplying or dividing an inequality by a negative number.)
Answer:
The answer is (-$200) to the left
Step-by-step explanation:
Solution
It is assumed that when a number is positive, it is a distance to the right, also when a number is negative, it is a distance to the left. If a positive number is referred to as deposit to a bank account, then a negative number is a withdrawal from that bank account.
So, If a positive number means addition, then a negative number would also mean subtraction.
The amount that represents a withdrawal of less than $200 would be (-$200)
Answer:
C = (2,2)
Step-by-step explanation:
B = (10 ; 2)
M = (6 ; 2)
C = (x ; y )
|___________|___________|
B (10;2) M (6;2) C ( x; y)
So:
dBM = dMC
√[(2-2)^2 + (6-10)^2] = √[(y-2)^2 + (x - 6)^2]
(2-2)^2 - (6-10)^2 = (y-2)^2 + (x - 6)^2
0 + (-4)^2 = (y-2)^2 + (x - 6)^2
16 = (y-2)^2 + (x - 6)^2
16 - (x - 6)^2 = (y-2)^2
Also:
2*dBM = dBC
2*√[(2-2)^2 + (6-10)^2] = √[(y-2)^2 + (x - 10)^2]
4*[(0)^2 + (-4)^2] = (y-2)^2 + (x - 10)^2
4*(16) = (y-2)^2 + (x - 10)^2
64 = (y-2)^2 + (x - 10)^2
64 = 16 - (x - 6)^2 + (x - 10)^2
48 = (x - 10)^2 - (x - 6)^2
48 = x^2 - 20*x + 100 - x^2 + 12*x - 36
48 = - 20*x + 100 + 12*x - 36
8*x = 16
x = 2
Thus:
16 - (x - 6)^2 = (y-2)^2
16 - (2 - 6)^2 = (y-2)^2
16 - (-4)^2 = (y-2)^2
16 - 16 = (y-2)^2
0 = (y-2)^2
0 = y - 2
2 = y
⇒ C = (2,2)
Answer:
y = -1/3 x
Step-by-step explanation:
what is the slope intercept form for x+3y=0
Slope intercept form solves for y:
x + 3y = 0
subtract x from both sides:
x + 3y - x = 0 - x
3y = -x
divide both sides by 3:
3y/3 = -x/3
y = -1/3 x
