The segment connecting a point on the preimage is equal to the segment connecting the point with its corresponding point on the image. Hence the relationship between the line of reflection is B. perpendicular bisector. It is not necessarily perpendicular as there are axis of symmetry that are not linear or 180 degrees
Answer:
m = 8 and c = 0
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = 8x ← is in slope- intercept form, that is y = 8x + 0
with m = 8 and c = 0
Things to remember the sum of the measures of the interior and exterior angles at each vertex is 180 (supplementary angles)
add and equal to 180
3x-5+5x+17= 180
8x+12=180
8x= 168
x=21
substitute in the algebraic expression for exterior angle
3(21) -5=
63-5=58
58 degrees is the exterior angle
hope this helps
Answer:
A)82.02 mi
B) 18.7° SE
Step-by-step explanation:
From the image attached, we can see the angles and distance depicted as given in the question. Using parallel angles, we have been able to establish that the internal angle at egg island is 100°.
A) Thus, we can find the distance between the home port and forrest island using law of cosines which is that;
a² = b² + c² - 2bc Cos A
Thus, let the distance between the home port and forrest island be x.
So,
x² = 40² + 65² - 2(40 × 65)cos 100
x² = 1600 + 4225 - (2 × 2600 × -0.1736)
x² = 6727.72
x = √6727.72
x = 82.02 mi
B) To find the bearing from Forrest Island back to his home port, we will make use of law of sines which is that;
A/sinA = b/sinB = c/sinC
82.02/sin 100 = 40/sinθ
Cross multiply to get;
sinθ = (40 × sin 100)/82.02
sin θ = 0.4803
θ = sin^(-1) 0.4803
θ = 28.7°
From the diagram we can see that from parallel angles, 10° is part of the total angle θ.
Thus, the bearing from Forrest Island back to his home port is;
28.7 - 10 = 18.7° SE