4,752 will be your answer
Answer:
q=-5
Step-by-step explanation:
6+q=1
Isolate the variable by subtracting 6 from both sides of the equation
q=1-6
q=-5
Answer:
The equivalent expression to the given expression is ![\sqrt[3]{32x^8y^{10}}=2x^2y^3\sqrt[3]{4x^2y}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B32x%5E8y%5E%7B10%7D%7D%3D2x%5E2y%5E3%5Csqrt%5B3%5D%7B4x%5E2y%7D)
Step-by-step explanation:
The given expression is ![\sqrt[3]{32x^8y^{10}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B32x%5E8y%5E%7B10%7D%7D)
To find the equivalent expression:
![\sqrt[3]{32x^8y^{10}}=(32x^8y^{10})^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B32x%5E8y%5E%7B10%7D%7D%3D%2832x%5E8y%5E%7B10%7D%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
We may write the above expression as below:

(using square root properties)
(combining the like terms and doing multiplication )
Therefore ![\sqrt[3]{32x^8y^{10}}=2x^2y^3\sqrt[3]{4x^2y}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B32x%5E8y%5E%7B10%7D%7D%3D2x%5E2y%5E3%5Csqrt%5B3%5D%7B4x%5E2y%7D)
Therefore the equivalent expression to the given expression is ![\sqrt[3]{32x^8y^{10}}=2x^2y^3\sqrt[3]{4x^2y}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B32x%5E8y%5E%7B10%7D%7D%3D2x%5E2y%5E3%5Csqrt%5B3%5D%7B4x%5E2y%7D)
Answer:
What is an inverse?
Recall that a number multiplied by its inverse equals 1. From basic arithmetic we know that:
The inverse of a number A is 1/A since A * 1/A = 1 (e.g. the inverse of 5 is 1/5)
All real numbers other than 0 have an inverse
Multiplying a number by the inverse of A is equivalent to dividing by A (e.g. 10/5 is the same as 10* 1/5)
What is a modular inverse?
In modular arithmetic we do not have a division operation. However, we do have modular inverses.
The modular inverse of A (mod C) is A^-1
(A * A^-1) ≡ 1 (mod C) or equivalently (A * A^-1) mod C = 1
Only the numbers coprime to C (numbers that share no prime factors with C) have a modular inverse (mod C)
Step-by-step explanation:
Please check image.