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Marat540 [252]
3 years ago
9

Find the sum 7a/a+5 + a/a-2

Mathematics
1 answer:
IRINA_888 [86]3 years ago
8 0

\dfrac{7a}{a+5}+\dfrac{a}{a-2} \\\dfrac{7a(a-2)+a(a+5)}{(a+5)(a-2)} \\\boxed{\dfrac{a(8a-9)}{(a+5)(a-2)}}

Hope this helps.

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The function f(x) = 4x + 5 has domain 0sxs 50. What is its range?<br> The range of the function is
MrMuchimi

9514 1404 393

Answer:

  range: 5 ≤ f(x) ≤ 205

Step-by-step explanation:

You can put the extreme values of x in this linear function to see its range:

  f(0) = 4·0 +5 = 5

  f(50) = 4·50 +5 = 205

The range is 5 ≤ f(x) ≤ 205.

7 0
3 years ago
2 trains leave the station at the same time. Train A is traveling 16 miles slower than train B. The two trains are 720 miles apa
Ber [7]

Answer: the rate of speed for train A is 66 miles per hour.

Step-by-step explanation:

Let x represent the speed of train B.

2 trains leave the station at the same time. Train A is traveling 16 miles per hour slower than train B. This means that the speed of train A would be x - 16 miles per hour.

The two trains are 720 miles apart after 4 hours. It means that both trains traveled a total distance of 720 miles in 4 hours.

Distance = speed × time

Distance travelled by train A after 4 hours is

4(x - 16) = 4x - 64

Distance travelled by train B after 4 hours is

4 × x = 4x

Since the total distance travelled by both trains is 720 miles, then

4x - 64 + 4x = 720

8x = 720 - 64 = 656

x = 656/8 = 82 miles per hour

The speed of train A would be

82 - 16 = 66 miles per hour.

6 0
3 years ago
Suppose a white dwarf star has a diameter of approximately 1.8083 to the power of 4 km. Use the formula 4n to the power of 2 to
aivan3 [116]

ANSWER:

The surface area of the star is 3.2700 x 10^{8} square kilometres.

EXPLANATIONS:

Diameter of the star = 1.8083 x 10^{4} Km.

Surface area of the star = 4n^{2}

Where n is the radius of the star.

So that;

n = \frac{ 1.8083 * 10^{4} }{2}

   = 0.90415 x 10^{4}

n =  0.90415 x 10^{4} Km

Thus,

Surface area = 4 x (0.90415*10^{4} )^{2}

                     = 326994889

Surface area = 3.2700 x 10^{8} km^{2}

Therefore, the surface area of the star is 3.2700 x 10^{8} square kilometres.

4 0
3 years ago
1. Consider the figure below where l2 intersects and m&lt;2 = 90°
ryzh [129]

angle 3 and angle 4 are adjacent and complementary.

angle 5 is a vertical angle to the combination of angle 3 and 2

angle 4 and angle 5 are adjacent, supplementary, and form a linear pair

If you want me to explain why, comment it, i just have no time to now.

6 0
3 years ago
Helppp please reallly fasttt!!!
Bingel [31]

Answer:

Step-by-step explanation:

3^{2}+ 7^{2} = EF^{2}

58=EF^{2}

EF=\sqrt{58}

4 0
3 years ago
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