Answer: No
Explanation:
According to factor theorem, if f(x)=0 then x is a factor of the given function or equation.
As x-1 is a factor
We equate x-1=0
x=1
Substituting in x^5-1, we have 1^5-1 =1-1=0.
Hence, it's a factor.
When coming to x^5+1, it would become 1^5+1=1+1=2
So x-1 isn't a factor of x^5+1.
3 and 17 that’s all there is to it, prime numbers are numbers that don’t divide by anything but itself and one
Answer:
h, j2, f, g, j1, i, k, l (ell)
Step-by-step explanation:
The horizontal asymptote is the constant term of the quotient of the numerator and denominator functions. Generally, it it is the coefficient of the ratio of the highest-degree terms (when they have the same degree). It is zero if the denominator has a higher degree (as for function f(x)).
We note there are two functions named j(x). The one appearing second from the top of the list we'll call j1(x); the one third from the bottom we'll call j2(x).
The horizontal asymptotes are ...
- h(x): 16x/(-4x) = -4
- j1(x): 2x^2/x^2 = 2
- i(x): 3x/x = 3
- l(x): 15x/(2x) = 7.5
- g(x): x^2/x^2 = 1
- j2(x): 3x^2/-x^2 = -3
- f(x): 0x^2/(12x^2) = 0
- k(x): 5x^2/x^2 = 5
So, the ordering least-to-greatest is ...
h (-4), j2 (-3), f (0), g (1), j1 (2), i (3), k (5), l (7.5)
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Step-by-step explanation:
77 is ur answer hope this helps u
