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Dafna11 [192]
2 years ago
10

Solve the expression and find the value of x.

Mathematics
2 answers:
vovangra [49]2 years ago
7 0

\large\underline{\sf{Solution-}}

\sf \dfrac{x + 1}{10}  -  \dfrac{3(x - 1)}{5}  = 2

\sf\longmapsto  \dfrac{x + 1}{10}  -  \dfrac{3x - 3}{5}  = 2

\sf\longmapsto \dfrac{(x + 1) - 2(3x - 3)}{10}   = 2

\sf\longmapsto \dfrac{x + 1 - (6x - 6)}{10}  = 2

\sf\longmapsto  \dfrac{x + 1 - 6x + 6}{10}  = 2

\sf\longmapsto \dfrac{ - 5x + 7}{10}  = 2

\sf\longmapsto - 5x + 7 = 20

\sf\longmapsto - 5x = 20 - 7

\sf\longmapsto - 5x = 13

\sf\therefore x =  -  \dfrac{13}{5}

Hence, the value of x will be -13/5 respectively.

ki77a [65]2 years ago
6 0

\huge \boxed{\mathfrak{Question} \downarrow}

\frac{x + 1}{10} - \frac{3(x - 1)}{5} = 2 \\

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

\frac { x + 1 } { 10 } - \frac { 3 ( x - 1 ) } { 5 } = 2 \\   \frac { x + 1 } { 10 } - \frac { 3 ( x - 1 ) } { 5 } =  \frac{2}{1}

Take a look at the denominators. The denominators are 10, 5 & 1. Their LCM is 10. So, multiply the fractions on both the sides of the equation by 10.

\frac { x + 1 } { 10 } - \frac { 3 ( x - 1 ) } { 5 } =  \frac{2}{1}  \\  \frac{x + 1}{10}  \times  \frac{1}{1}  -  \frac{3x - 3}{5}  \times  \frac{2}{2}    =  \frac{2}{1} \times  \frac{10}{10}   \\  \frac{x + 1}{10}  -  \frac{6x - 6}{10}  =  \frac{20}{10}

Now cancel the denominators (as they have the same value) & take the numerators.

x + 1 - (6x - 6) = 20 \\

Now, simplify it.

x + 1 - (6x - 6) = 20 \\ x + 1 - 6x + 6 = 20 \\ x - 6x + 1 + 6 = 20 \\  - 5x + 7 = 20 \\  - 5x = 13 \\    x = -\frac{13}{5} \\ \boxed{ \boxed{ \bf x =   - \frac{13}{5}  =\: - 2 \frac{3}{5}  =  - 2.6}}

__________________

Hope it'll help you!

ℓu¢αzz ッ

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