Their total expenses are ...
.. $1.50 +3.00 +1.25 = $5.75
Their profit is the difference between their charge and their cost:
.. $25.00 -5.75 = $19.25
The correct choice is ...
B) $19.25
Answer:
A.) 588329.896
B.) 274300
C.) 1657.18474
D.) 1.002
(All answers unrounded.)
Explanation:
I converted each unit to the unit used in the other number (E.g., for question A I converted tons to kilograms, and then finished solving.)
![\bf ~~~~~~\textit{initial velocity} \\\\ \begin{array}{llll} ~~~~~~\textit{in feet} \\\\ h(t) = -16t^2+v_ot+h_o \end{array} \quad \begin{cases} v_o=\stackrel{64}{\textit{initial velocity of the object}}\\\\ h_o=\stackrel{0\qquad \textit{from the ground}}{\textit{initial height of the object}}\\\\ h=\stackrel{}{\textit{height of the object at "t" seconds}} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~%5Ctextit%7Binitial%20velocity%7D%20%5C%5C%5C%5C%20%5Cbegin%7Barray%7D%7Bllll%7D%20~~~~~~%5Ctextit%7Bin%20feet%7D%20%5C%5C%5C%5C%20h%28t%29%20%3D%20-16t%5E2%2Bv_ot%2Bh_o%20%5Cend%7Barray%7D%20%5Cquad%20%5Cbegin%7Bcases%7D%20v_o%3D%5Cstackrel%7B64%7D%7B%5Ctextit%7Binitial%20velocity%20of%20the%20object%7D%7D%5C%5C%5C%5C%20h_o%3D%5Cstackrel%7B0%5Cqquad%20%5Ctextit%7Bfrom%20the%20ground%7D%7D%7B%5Ctextit%7Binitial%20height%20of%20the%20object%7D%7D%5C%5C%5C%5C%20h%3D%5Cstackrel%7B%7D%7B%5Ctextit%7Bheight%20of%20the%20object%20at%20%22t%22%20seconds%7D%7D%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D)

Check the picture below, it hits the ground at 0 feet, where it came from, the ground, and when it came back down.
Answer:
the area would be 0.4 or 40%
Step-by-step explanation:
The computation of the area is given below:
But before that the level of the density is
The density level is
= 1 ÷ (3 - 0)
= 1 ÷ 3
Area from 0 miles to 1.2 miles
= (1 ÷ 3) × (1.2 - 0)
= 0.4 or 40 %
Hence, the area would be 0.4 or 40%
the same is considered and relevant too
Answer:
<u><em>Yes.</em></u>
Step-by-step explanation:
<em>To find the answer we will put it into the equation, since</em><em><u> x = 1 and y = 2</u></em><em> we will write it like this, </em><u><em>6(1) - 2 > 3.</em></u><em> Since </em><u><em>6 x 1 = 6</em></u><em>, we will now </em><u><em>subtract 6 from 2 which equals 4</em></u><em>. Therefore, the equation is </em><u><em>correct because 4 is bigger than 3.</em></u>