Answer:
I guess it is C.
Explanation:
Because a gene is the basic unit of heredity that determines a offspring's characteristic, my guess is that the answer is C
(Hope this helped!)
If each subunit of a hemoglobin protein molecule carries a heme group and a hemoglobin protein molecule is made of four subunits, two α and two β, we can simply multiply four (number of heme groups that can be found in one hemoglobin protein molecule) by three (number of hemoglobin protein molecules considered). 4×3=12
There are twelve heme groups in three hemoglobin protein molecules.
Answer:
See the answer below.
Explanation:
<em>Let the allele for eye color be represented by A. Blue is dominant over brown eye color, hence, blue allele would be A while brown eye allele would be a.</em>
Two parents have the genotype blue/brown which is equivalent to Aa.
Aa x Aa
AA 2Aa aa
blue eyes blue eyes brown eyes
a. Different possible outcomes: AA blue eyes, Aa blue eyes, and aa brown eyes.
b. Probability of a child from the cross having brown/brown (aa) genotype = 1/4 or 25%
c. Probability that the child would have blue eye color = 3/4 or 75%
Answer:
The final product is four gametes, two of them with 5 chromosomes, and the other two with 3 chromosomes each.
Explanation:
If nondisjunction occurs during meiosis 1, a pair of homologous chromosomes fail to separate, and one of the daughter cells will have the two chromosomes while the other cell will not get any chromosome from the pair.
If meiosis 1 occurs normally, but nondisjunction occurs in meiosis 2, sister chromatids fail to separate.
The usual process of meiosis produces four daughter haploid cells (n) from a diploid germ cell (2n). Each daughter cell is haploid because they have half the number of chromosomes of the original one.
If the diploid number of the original cell is 8 (2n=8), then under normal conditions, each haploid daughter cell should have 4 chromosomes (n = 4).
But in the exposed example, one pair of homologous chromosomes experiences nondisjunction during meiosis I (in the attached file, you will recognize this pair as the red one). The other chromosomes separate as usual. So one of the daughter cells will have one extra chromosome than expected (five instead of four), and the other daughter cell will lack one chromosome (three instead of four). Meiosis II occurs normally. The final result is the formation of four gametes, two of them with 5 chromosomes, and the other two with 3 chromosomes each.
C. spinal nerves
it is the answer to your question.