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3 years ago

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recipe calls for 2 2/4 cups of raisins but Julie only has one cup 1/4 cup measuring cup how many 1/4 cup does truly need to meas

ure out 2 2/4 cups of raisins

1 answer:

vfiekz [6]3 years ago

3 0

Answer:

4 cups

Step-by-step explanation:

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Are these arithmetic sequences:

VladimirAG [237]

Answer:

1. No

2. Yes

3. Yes

4. Yes

Step-by-step explanation:

In 1. the difference between each term is not constant.(it goes up by, 2, 4, 6)

2. The terms increase by the same amount(it all goes up by 3)

3. The terms decrease by the same amount(it all goes down by 5)

4. The terms increase by the same amount(it all goes up by 6)

8 0

3 years ago

Delilah does 184184184 jumping jacks in 444 minutes. She does her jumping jacks at a constant rate. How many jumping jacks can D

valkas [14]

I'm assuming you didn't mean to repeat each number 3 times.

If she did 184 jumping jacks in 4 minutes that means she did 46 jumping jacks per minute.

4 0

3 years ago

Read 2 more answers

Trapezoid A B C D is shown. A diagonal is drawn from point B to point D. Sides B C and A D are parallel. Sides B A and C D are c

elena-s [515]

Answer:

40 degrees un edge

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Find integra of xlnxdx

Mademuasel [1]

Answer:

$\dfrac{1}{2}x^2\ln x - \dfrac{1}{4}x^2+\text{C}$

Step-by-step explanation:

<u>Fundamental Theorem of Calculus</u>

$\displaystyle \int \text{f}(x)\:\text{d}x=\text{F}(x)+\text{C} \iff \text{f}(x)=\dfrac{\text{d}}{\text{d}x}(\text{F}(x))$

If differentiating takes you from one function to another, then integrating the second function will take you back to the first with a <u>constant of integration</u>.

$\boxed{\begin{minipage}{4 cm}\underline{Integrating $x^n$}\\\\$\displaystyle \int x^n\:\text{d}x=\dfrac{x^{n+1}}{n+1}+\text{C}$\end{minipage}}$

Increase the power by 1, then divide by the new power.

Given <u>indefinite integral</u>:

$\displaystyle \int x \ln x \:\: \text{d}x$

To integrate the given integral, use Integration by Parts:

$\boxed{\begin{minipage}{5 cm}\underline{Integration by parts} \\\\$\displaystyle \int u \dfrac{\text{d}v}{\text{d}x}\:\text{d}x=uv-\int v\: \dfrac{\text{d}u}{\text{d}x}\:\text{d}x$ \\ \end{minipage}}$

$\text{Let }u=\ln x \implies \dfrac{\text{d}u}{\text{d}x}=\dfrac{1}{x}$

$\text{Let }\dfrac{\text{d}v}{\text{d}x}=x \implies v=\dfrac{1}{2}x^2$

Therefore:

$\begin{aligned}\displaystyle \int u \dfrac{dv}{dx}\:dx & =uv-\int v\: \dfrac{du}{dx}\:dx\\\\\implies \displaystyle \int x \ln x\:\:\text{d}x & = \ln x \cdot \dfrac{1}{2}x^2-\int \dfrac{1}{2}x^2 \cdot \dfrac{1}{x}\:\:dx\\\\& = \dfrac{1}{2}x^2\ln x -\int \dfrac{1}{2}x\:\:dx\\\\& = \dfrac{1}{2}x^2\ln x - \dfrac{1}{4}x^2+\text{C}\end{aligned}$

Learn more about integration here:

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5 0

2 years ago

What is the greatest acceptable length for a package that has a square base measuring 12 in. by 12 in.

geniusboy [140]

Ahh I’m not smart so imma just guess not saying it’s right . 24 in?

6 0

3 years ago