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Maru [420]
2 years ago
8

BRAINLIEST AND 100 POINTS

Mathematics
1 answer:
const2013 [10]2 years ago
5 0

Answer:

2

Step-by-step explanation:

2(3j + 4 + 9j) = 56

24j + 8 = 56

2(12j + 4) = 56

You might be interested in
5(x 1) − 8 = 5x(2 − 4)
svp [43]
Answer:
5 x (2 - 4)
5x-8= -10x
15x=8
x=8/15

Hope this helps!

3 0
3 years ago
Find the mean of the integers<br> -16,-27,21,-19,14,-3
babunello [35]
To find the mean all you have to do is add all the numbers...
you should get -30
 and divide by a number of numbers, there are 6
 so -30/6 is -5
5 0
3 years ago
In a naval engagement, one-third of the fleet was captured, one-sixth was sunk, and two ships were destroyed by fire. One-sevent
Otrada [13]

Answer:

60 ships.

Step-by-step explanation:

Let the total number of ships in the naval fleet be represented by x

One-third of the fleet was captured = 1/3x

One-sixth was sunk = 1/6x

Two ships were destroyed by fire = 2

Let surviving ships be represented by y

One-seventh of the surviving ships were lost in a storm after the battle = 1/7y

Finally, the twenty-four remaining ships sailed home

The 24 remaining ships that sailed home =

y - 1/7y = 6/7y of the surviving fleet sailed home.

Hence

24 = 6/7y

24 = 6y/7

24 × 7/ 6

y = 168/6

y = 28

Therefore, total number of ships that survived is 28.

Surviving ships lost in the storm = 1/7y = 1/7 × 28 = 4

Total number of ships in the fleet(x) =

x = 1/3x + 1/6x + 2 + 28

Collect like terms

x - (1/3x + 1/6x) = 30

x - (1/2x) = 30

1/2x = 30

x = 30 ÷ 1/2

x = 30 × 2

x = 60

Therefore, ships that were in the fleet before the engagement were 60 ships.

3 0
2 years ago
Simplify.
ASHA 777 [7]

Answer:

C

Step-by-step explanation:

The answer is 16x-20. First, you have to distribute 12 and 4 making the equation 12x-48+4x+28. Then, you combine the like terms giving you 16x-20. Hope this helped.

4 0
3 years ago
How can you write 9.85 in expanded form?
s2008m [1.1K]
Expanded form: 9.0+0.80+0.05
6 0
3 years ago
Read 2 more answers
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