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Maru [420]
2 years ago
8

BRAINLIEST AND 100 POINTS

Mathematics
1 answer:
const2013 [10]2 years ago
5 0

Answer:

2

Step-by-step explanation:

2(3j + 4 + 9j) = 56

24j + 8 = 56

2(12j + 4) = 56

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What is 2 times 8976543210?
blagie [28]
2*8976543210= 17953086420
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3 years ago
Read 2 more answers
How do I round up one number ow do I round up one numder
Alisiya [41]

Answer:How do I round up one number how do I round up one number you word where not spell properly for the question

Step-by-step explanation:Rounding means making a number simpler but keeping its value close to what it was.

The result is less accurate, but easier to use.

round 73 is 70, 76 is 80

Example: 73 rounded to the nearest ten is 70, because 73 is closer to 70 than to 80. But 76 goes up to 80.

Common Method

3 0
3 years ago
HELP ASAP<br> I NEED HELP
Karo-lina-s [1.5K]

Answer:

1;27

Step-by-step explanation:

5 0
3 years ago
a counter top is in the shape of a trapizoid . the lengths of the base is 70 1/2 and 65 1/2 inches long. the area of the counter
Grace [21]
I attached a photo of the work below :-) 

Area of a trapezoid= [(a+b)÷2]h
1,224 in²= [(65.5 in+70.5in)÷2]h
1,224in²= (136÷2)h
1,224 in²= 68h
(1,224 in²÷68)= 68h÷68 (elimination)
h= 18 inches

4 0
3 years ago
The graph of F ( x ) = 4/x2 - 2x - 3 is shown <br> for which values of X is f ( x ) decreasing
Elza [17]

Hi there!

\large\boxed{(-\infty, \sqrt[3]{-4}) \text{ and } (0, \infty) }

We can find the values of x for which f(x) is decreasing by finding the derivative of f(x):

f(x) = \frac{4}{x^2} - 2x - 3

Taking the derivative gets:

f'(x) = -\frac{8}{x^3} - 2

Find the values for which f'(x) < 0 (less than 0, so f(x) decreasing):

0 = -8/x³ - 2

2 = -8/x³

2x³ = -8

x³ = -4

x = \sqrt[3]{-4}

Another critical point is also where the graph has an asymptote (undefined), so at x = 0.

Plug in points into the equation for f'(x) on both sides of each x value to find the intervals for which the graph is less than 0:

f'(1) = -8/1 - 2 = -10 < 0

f'(-1) = -8/(-1) - 2 = 6 > 0

f'(-2) = -8/-8 - 2 = -1 < 0

Thus, the values of x are:

(-\infty, \sqrt[3]{-4}) \text{ and } (0, \infty)

6 0
3 years ago
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