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4 years ago

Simplify.

Mathematics

1 answer:

ASHA 777 [7]4 years ago

4 0

Answer:

Step-by-step explanation:

The answer is 16x-20. First, you have to distribute 12 and 4 making the equation 12x-48+4x+28. Then, you combine the like terms giving you 16x-20. Hope this helped.

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Help asaaaap pls !!!!!

tatyana61 [14]

Answer:

Step-by-step explanation:

for (10,5)

5 - 5 = 2(10 - 10) = 0

for (4,-7)

-7 - 5 = 2(4 - 10) = -12

7 0

3 years ago

Given △XPS≅△DNF, find the values of x and y.

White raven [17]

Answer:

x = 3

y = 15

Step-by-step explanation:

If △XPS ≅△DNF, their corresponding sides would be congruent. This implies that:

XP ≅ DN

PS ≅ NF

XS ≅ DF

Given that:

XP = 4y - 3

DN = 57

NF = 51

XS = 17x + 3

DF = 54

Therefore:

XP = DN

4y - 3 = 57 (Substitution)

Add 3 to both sides

4y = 57 + 3

4y = 60

Divide both sides by 4

y = 60/4

y = 15

Also,

XS = DF

17x + 3 = 54 (substitution)

Subtract 3 from each side

17x = 54 - 3

17x = 51

Divide both sides by 17

x = 51/17

x = 3

4 0

3 years ago

. 1<br> Find f<br> for the function f.<br> f(x) = 3x² + 3, x > 0<br> And find the domain

konstantin123 [22]

Answer:

y = $\sqrt{\frac{x-3}{3} }$

Domain = [3, infinity)

Step-by-step explanation:

x = 3y^2 + 3

3y^2 = x - 3

y^2 = (x-3)/3

y = $\sqrt{\frac{x-3}{3} }$

8 0

3 years ago

A ball is projected in to the air. Its height at time t is given by the equation

Ksju [112]

The equation gives the height of the ball. That is, h is the height of the ball. t is the time. Since we are looking for the time at which the height is 8 (h=8), we need to set the equation equal to 8 and solve for t. We do this as follows:

$h=-16 t^{2} +60t+1$
$8=-16 t^{2} +60t+1$
$16 t^{2} -60t-1+8=0$
$16 t^{2} -60t+7=0$

This is a quadratic equation and as it is set equal to 0 we can solve it using the quadratic formula. That formula is:
$t= \frac{-bplus minus \sqrt{ b^{2}-4ac } }{2a}$
You might recall seeing this as "x=..." but since our equation is in terms of t we use "t-=..."

In order to use the formula we need to identify a, b and c.
a = the coefficient (number in front of) $t^{2}$ = 16.
b = the coefficient of t = -60
c = the constant (the number that is by itself) = 7

Substituting these into the quadratic formula gives us:
$t= \frac{-(-60)plus minus \sqrt{ (-60)^{2}-4(16)(7) } }{2(16)}$
$t= \frac{60plus minus \sqrt{3600-448 } }{32}$
$t= \frac{60plus minus \sqrt{3152 } }{32}$

As we have "plus minus" (this is usually written in symbols with a plus sign over a minus sign) we split the equation in two and obtain:
$t= \frac{60+56.1426}{32} =3.63$
and
$t= \frac{60-56.1426}{32} =.12$

So the height is 8 feet at t = 3.63 and t=.12

It should make sense that there are two times. The ball goes up, reaches it's highest height and then comes back down. As such the height will be 8 at some point on the way up and also at some point on the way down.

3 0

4 years ago

Type the expression that results from the following series of steps:

kvv77 [185]

Answer:

$\frac{x - 3}{6}$

Step-by-step explanation:

First, subtract 3 from x

This will get you the expression x - 3

Now, divide this by 6.

This will get you the expression $\frac{x - 3}{6}$

So, the final expression from the steps is $\frac{x - 3}{6}$

3 0

3 years ago