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3 years ago

What is the vertex of the quadratic function f(x) = (x-8)(x - 2)?

Mathematics

1 answer:

frosja888 [35]3 years ago

6 0

Answer:

The vertex is at (5, -9)

Step-by-step explanation:

The vertex is halfway between the zeros

f(x) = (x-8)(x - 2)

0 = (x-8)(x - 2)

x=8 and x=2 are the two zeros

(8+2)/2 = 10/2 = 5

The x coordinate is at 5

The y coordinate is found by substituting the x coordinate into the function

f(5) = (5-8)(5 - 2) = -3 (3) = -9

The vertex is at (5, -9)

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Cos(0.5)+cos(0.5+2(3.14159265))+cos(0.5+4(3.14159265))

aleksandr82 [10.1K]

Answer:

2.63274768567

Step-by-step explanation:

First, note that 3.1415... is p, so 2(3.1415...) is 2pi and 4(3.1415...) is 4pi.

2pi and 4pi are full rotations, which will lead to the same cosine (i.e. cos(x) = cos (x+2pi) = cos(x+4pi) = ... = cos (x+2k*pi)).

So, the expression equals cos0.5 + cos 0.5 + cos0.5 = 3cos0.5 = 3(0.87758256189) = 2.63274768567

I hope this helps! :)

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3 years ago

Elenna [48]

Parallel lines are in the same plane, never intersect, and have the same slope.

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3 years ago

What is the slope of the line that passes through the points A(0, 1) and B(2, 7)?

Alenkinab [10]

Answer:

Step-by-step explanation:

We can use the formula [ y2-y1/x2-x1 ] to solve.

7-1/2-0

6/2

Best of Luck!

4 0

3 years ago

3+11x9-9x11 what is the answer

Rom4ik [11]

Your answer would be 3

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3 years ago

Read 2 more answers

Find the measure of the indicated angle to the nearest degree.

Paladinen [302]

Using Pythagorean triplete

$\\ \sf\longmapsto h^2=33^2+8^2$

$\\ \sf\longmapsto h^2=1089+64$

$\\ \sf\longmapsto h^2=1153$

$\\ \sf\longmapsto h=\sqrt{1153}$

$\\ \sf\longmapsto h=33.9$

$\\ \sf\longmapsto h\approx34$

Now

$\boxed{\sf sin\theta=\dfrac{h}{P}}$

$\\ \sf\longmapsto sin\theta=\dfrac{34}{8}$

$\\ \sf\longmapsto sin\theta=4.2$

$\\ \sf\longmapsto 2sin\theta=sin60$

$\\ \sf\longmapsto \theta=30°$

3 0

2 years ago