What is the vertex of the quadratic function f(x) = (x-8)(x - 2)?
1 answer:
Answer:
The vertex is at (5, -9)
Step-by-step explanation:
The vertex is halfway between the zeros
f(x) = (x-8)(x - 2)
0 = (x-8)(x - 2)
x=8 and x=2 are the two zeros
(8+2)/2 = 10/2 = 5
The x coordinate is at 5
The y coordinate is found by substituting the x coordinate into the function
f(5) = (5-8)(5 - 2) = -3 (3) = -9
The vertex is at (5, -9)
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