What is the vertex of the quadratic function f(x) = (x-8)(x - 2)?

Mathematics

1 answer:

frosja888 [35]3 years ago

6 0

Answer:

The vertex is at (5, -9)

Step-by-step explanation:

The vertex is halfway between the zeros

f(x) = (x-8)(x - 2)

0 = (x-8)(x - 2)

x=8 and x=2 are the two zeros

(8+2)/2 = 10/2 = 5

The x coordinate is at 5

The y coordinate is found by substituting the x coordinate into the function

f(5) = (5-8)(5 - 2) = -3 (3) = -9

The vertex is at (5, -9)

You might be interested in

How do I solve this?

Ivenika [448]

$\overline{XS}\cong\overline{YT}\Rightarrow 3m+7=4.2m+5\ \ \ |-7\\\\3m=4.2m-2\ \ \ \ |-4.2m\\\\-1.2m=-2\ \ \ \ |:(-1.2)\\\\m=\dfrac{2}{1.2}\\\\m=\dfrac{20}{12}\\\\m=\dfrac{5}{3}\to m=1\dfrac{2}{3}$

$\overline{YS}\cong\overline{XT}\Rightarrow3\dfrac{1}{2}r+2=2r+5\ \ \ \ |-2\\\\3\dfrac{1}{2}r=2r+3\ \ \ \ |-2r\\\\1\dfrac{1}{2}r=3\ \ \ |\cdot2\\\\3r=6\ \ \ \ |:3\\\\r=2$