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leva [86]
2 years ago
15

I have 30 ones,82thousands,4 hundred thousands,60 tens,and 100 hundreds , what number am I?​

Mathematics
1 answer:
Anvisha [2.4K]2 years ago
8 0
You add all the numbers so it become 400,082,190

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The clock hand made a 90 degree turn. It is not a 3/4 fraction.

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The school band is ordering health bars to sell for a fundraiser. The company that sells the bars charges $0.40 per bar plus $20
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A random sample of 36 students at a community college showed an average age of 25 years. Assume the ages of all students at the
Pavel [41]

Answer:

98% confidence interval for the average age of all students is [24.302 , 25.698]

Step-by-step explanation:

We are given that a random sample of 36 students at a community college showed an average age of 25 years.

Also, assuming that the ages of all students at the college are normally distributed with a standard deviation of 1.8 years.

So, the pivotal quantity for 98% confidence interval for the average age is given by;

             P.Q. = \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \bar X = sample average age = 25 years

            \sigma = population standard deviation = 1.8 years

            n = sample of students = 36

            \mu = population average age

So, 98% confidence interval for the average age, \mu is ;

P(-2.3263 < N(0,1) < 2.3263) = 0.98

P(-2.3263 < \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } < 2.3263) = 0.98

P( -2.3263 \times {\frac{\sigma}{\sqrt{n} } < {\bar X - \mu} < 2.3263 \times {\frac{\sigma}{\sqrt{n} } ) = 0.98

P( \bar X - 2.3263 \times {\frac{\sigma}{\sqrt{n} } < \mu < \bar X +2.3263 \times {\frac{\sigma}{\sqrt{n} } ) = 0.98

98% confidence interval for \mu = [ \bar X - 2.3263 \times {\frac{\sigma}{\sqrt{n} } , \bar X +2.3263 \times {\frac{\sigma}{\sqrt{n} } ]

                                                  = [ 25 - 2.3263 \times {\frac{1.8}{\sqrt{36} } , 25 + 2.3263 \times {\frac{1.8}{\sqrt{36} } ]

                                                  = [24.302 , 25.698]

Therefore, 98% confidence interval for the average age of all students at this college is [24.302 , 25.698].

8 0
3 years ago
Please help with question 2-6! no one wants to help me out
Zanzabum

Answer:

OMGGGGG I remmeber this :,) But sadly I failed math so sorry :((

Step-by-step explanation:

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3 years ago
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PLZ HELP What is the mode interval for the histogram? Science Test Scores Frequency No Бел о об - 1 50-59 60-69 70-79 80-89 90-1
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Answer: You are correct. The mode is between 90 and 100

This is because the tallest bar corresponds to this interval. The mode is the most frequent value.

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