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BabaBlast [244]
3 years ago
8

-4 (5y + 5) = -120 y =

Mathematics
2 answers:
Sedbober [7]3 years ago
6 0

-4 (5y + 5) = -120

multiply the bracket by -4

(-4)(5y)=-20y

(-4)(5)=-20

-20y-20=-120

move -20 to +20

-20y-20+20=-120+20

-20y=-120+20

-20y=-100

divide both sides by -20 to get y by itself

-20y/-20=-100/-20

Answer: y=5

Serga [27]3 years ago
6 0

Answer:

Step-by-step explanation:

-4(5y + 5) = -120  

-4*5 y = -20 y

-4*5 = 20

-20 y + 20 = -120

         -20      -20

______________

-20 y             -100

-20 y               -20

y=50

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PLEASE HELP ME!!!! I NEED THIS QUICKLY!!
zloy xaker [14]

Part A: y=-\frac{5}{4} x+\frac{35}{2} is the equation of the line.

Part B: Anika worked 17.5 hours on day 0.

Part C: The setup time decreases with 1 hour and 15 min per day.

Explanation:

Part A: Let us find the equation of the line using the points (2,15) and (6,10)

The equation of the line is given by,

y-y_{1}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \cdot\left(x-x_{1}\right)

Substituting, we get,

y-15=\frac{10-15}{6-2} (x-2)

Simplifying, we have,

y-15=-\frac{5}{4} (x-2)

y-15=-\frac{5}{4} x+\frac{5}{2}

Subtracting both sides by 15, we get,

y=-\frac{5}{4} x+\frac{35}{2}

Hence, the equation of the line is y=-\frac{5}{4} x+\frac{35}{2}

Part B: To determine the number of hours Anika worked on day 0, let us substitute x = 0 in the equation of the line.

Thus, we get,

y=\frac{35}{2}\\y=17.5

Hence, Anika worked 17.5 hours on day 0.

Part C: The setup time decrease per day can be determined using the slope.

The formula for slope is given by

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

Substituting , we have,

m=\frac{10-15}{6-2}=-\frac{5}{4}

Converting the fraction into hours and minutes, we get,

-\frac{5}{4}\times60=-75 min

Since, 1 hour = 60 min

Subtracting 60 and 75 = 15 min

Thus, the setup time decreases with 1 hour and 15 min per day.

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3 years ago
Read 2 more answers
If 3 = 1/2gt^2, make t the subject of the formula<br>​
Montano1993 [528]

Answer:

t = √1.5/g

Step-by-step explanation:

1/2gt^2 = 3

Divide both sides by 1/2

gt^2 = 1.5

Divide both sides by g

t^2 = 1.5/g

Square root both sides

t = √1.5/g

5 0
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