<span>The correct option is: (C) a⊥b, by Perpendicular Transversal Theorem
Explanation:
Perpendicular Transversal Theorem states that in a plane, if a line is perpendicular to one of two parallel lines, then it is perpendicular to the other line also.
As the line b is perpendicular to the line c and the line c is parallel to the line a, hence the line a is perpendicular to the line b. Therefore, the correct option is (C) a⊥b, by Perpendicular Transversal Theorem
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The question did not show the original vertices of A, B, and C.
Generally, for a triangle ABC that is dilated by a scale factor of four to form triangle A'B'C', the coordinates of vertices A', B', C' are:
For A(x, y)
The coordinate of vertex A' will be A' (4x, 4y)
For B(x, y)
The coordinate of vertex B' will be B' (4x, 4y)
For C(x, y)
The coordinate of vertec C' will be C' (4x, 4y)
The slope of a line parallel to y= 5x + 2
This is because a parallel line will have the same slope as the line it’s trying to be parallel to. In this case, 5 :)
Answer:
x=55
Step-by-step explanation:
2x-7=103
2x=103+7
2x=110
x=55