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2 years ago

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Question 14 of 25

1 answer:

inessss [21]2 years ago

4 0

A. Is correct because unless you want to have 10 dimes in April and 20 dimes in May you would normally just have however many you have if you know what I mean

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notka56 [123]

$\dfrac{2}{\sqrt3\cos x+\sin x}=\sec\left(\dfrac{\pi}{6}-x\right)\\\\\dfrac{2}{\sqrt3\cos x+\sin x}=\dfrac{1}{\cos\left(\dfrac{\pi}{6}-x\right)}\ \ \ \ \ (*)\\----------------\\\\\cos\left(\dfrac{\pi}{6}-x\right)\ \ \ \ |\text{use}\ \cos(x-y)=\cos x\cos y+\sin x\sin y\\\\=\cos\dfrac{\pi}{6}\cos x+\sin\dfrac{\pi}{6}\sin x=\dfrac{\sqrt3}{2}\cos x+\dfrac{1}{2}\sin x=\dfrac{\sqrt3\cos x+\sin x}{2}\\------------------------------$

$(*)\\R_s=\sec\left(\dfrac{\pi}{6}-x\right)=\dfrac{1}{\cos\left(\dfrac{\pi}{6}-x\right)}=\dfrac{1}{\dfrac{\sqrt3\cos x+\sin x}{2}}\\\\=\dfrac{2}{\sqrt3\cos x+\sin x}=L_s$

6 0

3 years ago

Read 2 more answers

it takes 52 minutes for 5 people to paint 5 walks. how many minutes does it take 20 people to paint 20 walks

Viktor [21]

Answer:

52min

Step-by-step explanation:

5 people..............5 walls............52 min

1 people...............5 walls...........52 x 5=260 min

1 people................20 walls.........260 x 4 =1040 min

20 people................20 walls........1040:20=52 min

7 0

3 years ago

Read 2 more answers

Which of the following is equivalent to log 7^ 50 rounded to three decimal places?

otez555 [7]

7^50
= 1.798 × 10^42

i am a mathematics teacher. if anything to ask please pm me

4 0

3 years ago

How long would the string be in meters if it is 120 centimeters

nexus9112 [7]

1 meter = 100 centimeters, so 120 centimeters equal to 1.2 meters.

4 0

3 years ago

4(3x^2y^4)^3 / (2x^3y^5)^4

tatyana61 [14]

Solving the expressions $\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}$ we get $\frac{27}{4x^{6}y^{8}}$

Step-by-step explanation:

We need to Solve the expression: $\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}$

Solving:

$\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}$

$=\frac{4(3^3x^6y^{12})}{(2^4x^{12}y^{20})}\\=\frac{4(27x^6y^{12})}{(16x^{12}y^{20})}\\=\frac{108x^6y^{12}}{16x^{12}y^{20}}$

Applying exponent rule: $\frac{x^a}{x^b}=x^{a-b}$

$=\frac{108x^{6-12}y^{12-20}}{16}\\=\frac{27x^{-6}y^{-8}}{4}$

Another exponent rule says: $x^{-a}=\frac{1}{x^a}=$

$=\frac{27}{4x^{6}y^{8}}$

So, solving the expressions $\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}$ we get $\frac{27}{4x^{6}y^{8}}$

Keywords: Solving Exponents

Learn more about Solving Exponents at:

#learnwithBrainly

8 0

3 years ago