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2 years ago

Question 14 of 25

1 answer:

4 0

A. Is correct because unless you want to have 10 dimes in April and 20 dimes in May you would normally just have however many you have if you know what I mean

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Five more than a number is three

Pavel [41]

I'm not sure if you use "x" as your variable, so:

# + 5 = 3 or x + 5 = 3

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3 years ago

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Answer FAST PLSSS ITS TO HARDD

noname [10]

the answer to this problem is no.

5 0

3 years ago

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What is the solution to x^4+ 4x^3<12x^2?

zavuch27 [327]

Answer: the answer is -6<x<0 or 0<x<2

Step-by-step explanation: brainlest please

5 0

4 years ago

Find all the zeros of 2x4+x3-14x2-19x-6 two of its zeros are -2 and -1

GalinKa [24]

Answer:

$-2,\ -1,\ -\dfrac{1}{2},\ 3.$

Step-by-step explanation:

Consider polynomial $2x^4+x^3-14x^2-19x-6.$

If x=-2 is its zero, then you can divide the polynomial $2x^4+x^3-14x^2-19x-6$ by $x+2$ and get

$2x^4+x^3-14x^2-19x-6=(x+2)(2x^3-3x^2-8x-3).$

If x=-1, then the polynomial $2x^4+x^3-14x^2-19x-6$ can be rewritten as

$2x^4+x^3-14x^2-19x-6=(x+2)(x+1)(2x^2-5x-3).$

The quadratic polynomial has roots

$x_{1,2}=\dfrac{-(-5)\pm\sqrt{(-5)^2-4\cdot2\cdot(-3)}}{2\cdot 2}=\dfrac{5\pm \sqrt{25+24}}{4}=\dfrac{5\pm \sqrt{49}}{4}=3,-\dfrac{1}{2}.$

Then the polynomial $2x^4+x^3-14x^2-19x-6$ has zeros $-2,\ -1,\ -\dfrac{1}{2},\ 3.$

7 0

3 years ago

At Kent Middle school, breakfast costs $1.25 and lunch costs $3.75. What percent of the costs of lunch is the cost of breakfast?

KATRIN_1 [288]

33.3 repeating
This can be simply found out by dividing 3.75 from 1.25
1.25 / 3.75 = .33

5 0

4 years ago