Ask question

Ask question

All categories

Karo-lina-s [1.5K]

3 years ago

5

Which statement best explains if the graph correctly represents the proportional relationship y = 3.5x? A graph of a coordinate

plane is shown. Points are graphed at 1 and 3.5 and 2 and 7. The points are joined by a line. It does, the points shown on the line would be part of y = 3.5x. It does not, proportions cannot be represented on a graph. It does not, the points shown on the line would not be part of y = 3.5x. It does, all proportions can be shown on the graph of this line.

1 answer:

Evgesh-ka [11]3 years ago

7 0

Answer:

It does, the points shown on the line would be part of $y=3.5x$

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form $y/x=k$ or $y=kx$

In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin

In this problem we have

$y=3.5x$

The slope is equal to $m=3.5$ ------> is a positive slope

The line passes through the origin

therefore

This linear equation represent a proportional variation

Verify the values of the points of the graph with the equation

For $x=1$

$y=3.5*1=3.5$ -----> is correct

For $x=2$

$y=3.5*2=7$ -----> is correct

You might be interested in

Help asap plzzzzzzzzzz

serg [7]

Based on what I know it’s B because the others have exponents and linear functions don’t have exponents

8 0

3 years ago

I really need help i i put a picture up but this thing do´s not let me post it with out a question ?

kobusy [5.1K]

Answer:

Step-by-step explanation:

$y=-x^{2} -5x-6$

$y=-(x^2+5x+6)$

$y=-(x+3)(x+2)$

Set each factors equal to zero.

$(x+3)=0 , x=-3$

$x+2=0 , x=-2$

The x-int is

$(-2,0)$

4 0

3 years ago

A meteorologist is monitoring the atmospheric pressure as his height above sea level varies. The meteorologist determines that t

Burka [1]

Answer:

The function $p(n)$ is represented by $p(n) = 103\cdot (0.88)^{n}$ .

Step-by-step explanation:

Statement indicates that atmospheric pressure decreases exponentially when height above sea level is increased. This fact is represented by the following model:

$p(n) = p_{o}\cdot r^{n}$ (Eq. 1)

Where:

$p_{o}$ - Atmospheric pressure at sea level, measured in kilopascals.

$r$ -Atmospheric pressure decrease rate, dimensionless.

$n$ - Height above sea level, measured in kilometers.

$p(n)$ - Current pressure, measured in kilopascals.

If we know that $p_{o} = 103\,kPa$ and $r = 0.88$ , the function $p(n)$ is represented by:

$p(n) = 103\cdot (0.88)^{n}$

4 0

3 years ago

. Lightning Strikes It has been said that the probability of being struck by lightning is about 1 in 750,000, but under what cir

mrs_skeptik [129]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

$P(U |D ) = 0.198$

b

$P(O\ n \ B) = 0.188$

c

$P(O | B) = 0.498$

Step-by-step explanation:

The total number of deaths is mathematically represented as

$T = 16 + 23 + \cdots + 16$

$T =623$

The total number of deaths in 1996 - 2000 is mathematically represented as

$T_a = 16 + 23+ \cdots + 30$

$T_a = 235$

The total number of deaths in 2001 - 2005 is mathematically represented as

$T_b = 17 + 16 + \cdots + 23$

$T_b = 206$

The total number of deaths in 2006 - 2010 is mathematically represented as

$T_c = 15 + 17 + \cdots + 16$

$T_d = 182$

Generally the the probability that it would occur under the tree given that the death was after 2000 is mathematically represented as

$P(U |D ) = \frac{P(A \ n\ U )}{P(A)}$

Here $P(A \ n\ U )$ represents the probability that it was after 2000 and it was under the tree and this is mathematically represented as

$P(A \ n\ U ) = \frac{Z}{ T}$

Here Z is the total number of death under the tree after 2000 and it is mathematically represented as

$Z = 35 + 42$

=> $Z = 77$

=> $P(A \ n\ U ) = \frac{77}{ 623}$

=>

Also

$P(A)$ is the probability of the death occurring after 2000 and this is mathematically represented as

$P(A) = \frac{T_b + T_c}{ T}$

=> $P(A) = \frac{ 206+ 182}{623}$

=>

So

$P(U |D ) = \frac{\frac{77}{ 623} }{ \frac{ 206+ 182}{623}}$

=> $P(U |D ) = 0.198$

Generally the probability that the death was from camping or being outside and was before 2001 is mathematically represented as

$P(O | B) = \frac{T_z}{ T}$

Here $T_z$ is the total number of death outside / camping before 2001 and the value is 117

So

$P(O \ n \ B) = \frac{117}{623}$

=> $P(O\ n \ B) = 0.188$

Generally the probability that the death was from camping or being outside given that it was before 2001 is mathematically represented as

$P(O | B) = \frac{ P( O \ n \ B)}{ P(B)}$

Here $P(B)$ is the probability that it was before 2001 , this is mathematically represented as

$P(B ) = \frac{T_a}{T}$

=> $P(B ) = \frac{235}{623}$

So

$P(O | B) = \frac{ \frac{117}{623}}{ \frac{235}{623}}$

=> $P(O | B) = 0.498$

5 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%7B%28x%20-%20y%29%7D%5E%7B2%7D%20" id="TexFormula1" title=" {(x - y)}^{2} " alt=" {(x - y)

Lubov Fominskaja [6]

Step-by-step explanation:

$= {(x - y)}^{2} \\ = {x}^{2} - 2xy + {y}^{2}$

3 0

3 years ago

Read 2 more answers