That'd be a total of 6 km east and 4 km north.
The distance traveled from Carol's starting point, along the path described, is
1 km + 4 km + 5 km = 10 km.
However, if you want the straight line distance from starting to end point, that would be found using the Pyth. Thm.:
sqrt [ (6 km)^2 + (4 km)^2 ] = sqrt(52) = 2sqrt(13) km
Answer:
HCF of (48,108) is 2
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Answer:
See below.
Step-by-step explanation:
a.
O is the origin, so its abscissa is 0. O: 0
The only point 4 units from O is A, so A: 4
Point C has a positive abscissa like A.
Points B and C have opposite abscissas. The only opposites are -3 and 3, but C is positive, and B is negative.
B: -3
C: 3
D: -4.5
E: -6
M = (4 + (-6))/2 = -1. M: -1
b.
OB = |0 - (-3)| = |3| = 3
DA = |-4.5 - 4| = |-8.5| = 8.5
Just add numbers to get to 45
Answer:
3.9 x 107
Step-by-step explanation: