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2 years ago

PLEASE ANSWER FAST I NEED HELP

Mathematics

1 answer:

miss Akunina [59]2 years ago

5 0

Answer:

The answer is bannana soomthie

Step-by-step explanation:

because if you read it slowly you can see that jamie and taylor are both juniors

You might be interested in

The phrase “y less than 7” translates to an equation.<br><br> True or False?

defon

Answer:

False, it translates to an inequality.

8 0

4 years ago

Find the missing side length

sasho [114]

Answer:

Missing side length = 54

Step-by-step explanation:

If both the triangles given in the picture are similar their corresponding sides will be proportional.

By applying this rule in the given similar triangles,

$\frac{35}{30}=\frac{49}{42}=\frac{63}{6x-6}$

$\frac{7}{6}=\frac{7}{6}= \frac{63}{6x-6}$

$\frac{7}{6}= \frac{63}{6x-6}$

$\frac{1}{6}= \frac{9}{6x-6}$

$\frac{1}{6}= \frac{9}{6(x-1)}$

$1=\frac{9}{x-1}$

$x-1=9$

$x=10$

Therefore, missing side length = $6x-6$

= $6(x-1)$

= $6(10-1)$

= $6\times 9$

= $54$

4 0

3 years ago

The top and bottom margins of a poster are each 12 cm and the side margins are each 8 cm. The area of printed material on the po

grin007 [14]

Answer:

Dimensions of printed poster are

length is 32 cm

width is 48 cm

Step-by-step explanation:

Let's assume

length of printed poster is x cm

width of printed poster is y cm

now, we can find area of printed poster

so, area of printed poster is

$=xy$

we are given that area as 1536

so, we can set it to 1536

$xy=1536$

now, we can solve for y

$y=\frac{1536}{x}$

now, we are given

The top and bottom margins of a poster are each 12 cm and the side margins are each 8 cm

so, total area of poster is

$A=(8+x+8)\times (12+y+12)$

$A=(x+16)\times (y+24)$

now, we can plug back y

$A=(x+16)\times (\frac{1536}{x}+24)$

now, we have to minimize A

so, we will find derivative

$A'=\frac{d}{dx}\left(\left(x+16\right)\left(\frac{1536}{x}+24\right)\right)$

we can use product rule

$A'=\frac{d}{dx}\left(x+16\right)\left(\frac{1536}{x}+24\right)+\frac{d}{dx}\left(\frac{1536}{x}+24\right)\left(x+16\right)$

$=\frac{d}{dx}\left(x+16\right)\left(\frac{1536}{x}+24\right)+\frac{d}{dx}\left(\frac{1536}{x}+24\right)\left(x+16\right)$

now, we can simplify it

$A'=-\frac{24576}{x^2}+24$

now, we can set it to 0

and then we can solve for x

$A'=-\frac{24576}{x^2}+24=0$

$-\frac{24576}{x^2}x^2+24x^2=0\cdot \:x^2$

$-24576+24x^2=0$

$x=32,\:x=-32$

Since, x is dimension

and dimension can never be negative

so, we will only consider positive value

$x=32$

now, we can solve for y

$y=\frac{1536}{32}$

$y=48$

so, dimensions of printed poster are

length is 32 cm

width is 48 cm

5 0

3 years ago

Help me with this please (7th g

erik [133]

The answer is 1,635 cause 33 times 50 is 1,650 then subtract 15 from 1,650. That's easy bro I'm in 5th grade and I know that.

3 0

3 years ago

please hurry!! i have a D in math

3241004551 [841]

Answer:

60, and m = 30, and 1 min 20.

Step-by-step explanation:

For A, the 60 is the starting point meaning that the temperature was intitally 60 degrees

For B, if we divided both sides by 2 we get the answer m = 30, meaning every minute, it was up 30 degrees.

For C, we know that in one minute it will be 90 degrees, so 60 seconds = 30 degrees. So lets divided both sides by 3 to get 10 degrees. We get 20 seconds. It will take 1 min and 20 for it to be 100 degrees.

Hopefully thats right.

4 0

3 years ago