All categories

3 years ago

The number 8,046 can be modeled using base ten blocks. How many of each type of block are needed to build the number?

Mathematics

2 answers:

MArishka [77]3 years ago

7 0

Answer:

the first one

Step-by-step explanation:

8 one thousand block is 8000

0 hundreds 000

4 tens. 40

6 ones. 6

8046

artcher [175]3 years ago

4 0

The answer you are looking for is A. 8 thousands blocks, 4 tens blocks, and 6 ones blocks.

This is because the 8 is in the thousands place (which equals 8 thousands blocks), the 4 is in the tens place (which equals the 4 tens blocks), and the 6 is the ones place (which equals the 6 ones blocks).

I hope this helps!

You might be interested in

In my pocket I have 8 quarters and 6 dimes. What fractional portion of the coins in my pocket are dimes

marin [14]

im pretty sure the answer is 3/4

7 0

3 years ago

Read 2 more answers

At what rate per annum ci will RS 2000 amount to RS 2315.35 in 3 years

Mashutka [201]

ANSWER:

Rate per annum at which CI will amount from RS 2000 to RS 2315.35 in 3 years is 5%

SOLUTION:

Given,

P = RS 2000

C.I = RS 2315.35

T = 3 years

We need to find the rate per annum. i.e. R = ?

We know that,

When interest is compound Annually:

$Amount $=\mathrm{P}\left(1+\frac{\mathrm{R}}{100}\right)^{n}$$

Where p = principal amount

r = rate of interest

n = number of years

$2315.35=2000 \times\left(1+\frac{R}{100}\right)^{3}$

$\left(1+\frac{R}{100}\right)^{3}=\frac{2315.35}{2000}$

$\left(1+\frac{R}{100}\right)^{3}=1.157$

$1+\frac{R}{100}=\sqrt[3]{1.157}$

$1+\frac{R}{100}=1.0500$

$\frac{R}{100}=1.05-1$

$\frac{R}{100}=0.05$

R = 5%

Hence, rate per annum is 5 percent.

3 0

3 years ago

Can someone help me

serg [7]

Your answer is D. right

4 0

3 years ago

Without actual division prove that x4 +2x3 -2x2 +2x -3 is exactly divisible by x2 +2x-3

Brut [27]

Answer:

Step-by-step explanation:

$\displaystyle\Large\boldsymbol{} x^4+2x^3-2x^2+2x-3= \\\\\\x^4+2x^2(x-1)+2x-\underbrace{2-1}_{-3}= \\\\\\x^4-1+2x^2(x-1)+2x-2 = \\\\\\(x^2-1)(x^2+1)+2x^2(x-1)+2(x-1) = \\\\\\\underline{(x-1)}(x+1)(x^2+1)+2x^2\underline{(x-1)} +2\underline{(x-1)} =\\\\\\(x-1)((x+1)(x^2+1)+2x^2+2)=\\\\\\(x-1)(x^3+x^2+2x^2+x+2+1)=\\\\\\(x-1)(x^3+3x^2+x+3) =\\\\\\(x-1)( \underline{(x+3)}x^2+\underline{(x+3)})=(x^2+1)\underbrace{(x-1)(x+3)}_{x^2+2x-3}= \\\\\\(x^2+1)(x^2+2x-3) : (x^2+2x-3)=x^2+1$

7 0

3 years ago

Find a fraction in between 21/34 and 34/55

sashaice [31]

Answer:

A fraction between that is 2311/3740

Step-by-step explanation:

This is because the denominator is simplified into one number and the fraction is taken from there.

3 0

3 years ago

Read 2 more answers