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Inessa05 [86]
3 years ago
5

Tim has a box of 15 markers he gives 3 markers each to 4 friends what expression can show the number of markers Tim has left

Mathematics
2 answers:
Ira Lisetskai [31]3 years ago
5 0
He will have 3 markers left
lutik1710 [3]3 years ago
3 0
(3 x 4) (15-12)
That is because each friend is getting 3 markers, there are four friends. so the product of that is minus the total number of markers he has.
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W+w+w+w+w+15-7 I got this wrong on a math question. I did 5w+8 = 13w ​
Aleonysh [2.5K]

w+w+w+w+w+15-7=\underbrace{w+w+w+w+w}_5+(15-7)\\\\=5w+8-\text{finish}\\\\\text{You can not add 5w and 8. These are different monomials.}

Example:

5w - five apples

8 - eight strawberries

5w + 8 = (five apples) + (eight strawberries) = 13 of what?

You can add only numbers of the same fruits.

4 0
3 years ago
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Find the value of x.
Gnoma [55]

Answer:

x = 10

Step-by-step explanation:

Since the triangle is right use the sine ratio to find x

sin30° = \frac{opposite}{hypotenuse} = \frac{5}{x}

cross- multiply

x × sin30° = 5 ( sin30° = 0.5 )

0.5x = 5 ( divide both sides by 0.5 )

x = 10

5 0
3 years ago
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Use the Shell Method to find the volume of the solid obtained by rotating region under the graph of f(x)=x^2+2 for 0≤x≤5 about x
Irina18 [472]

For each <em>x</em> in the interval 0 ≤ <em>x</em> ≤ 5, the shell at that point has

• radius = 5 - <em>x</em>, which is the distance from <em>x</em> to <em>x</em> = 5

• height = <em>x</em> ² + 2

• thickness = d<em>x</em>

and hence contributes a volume of 2<em>π</em> (5 - <em>x</em>) (<em>x</em> ² + 2) d<em>x</em>.

Taking infinitely many of these shells and summing their volumes (i.e. integrating) gives the volume of the region:

\displaystyle 2\pi \int_0^5 (5-x)(x^2+2)\,\mathrm dx=2\pi\int_0^5 (10-2x+5x^2-x^3)\,\mathrm dx=\boxed{\frac{925\pi}6}

4 0
2 years ago
Theorem: The segment joining the midpoints of two sides of a triangle is parallel to the third side and half its length. A two-c
natali 33 [55]

Answer:  By the slope formula.

Step-by-step explanation:

Given: ABC is a triangle (shown below),

In which A≡(6,8), B≡(2,2) and C≡(8,4)

And, D and E are the mid points of the line segments AB and BC respectively.

Prove: DE║AC and DE = AC/2

Proof:

Since, And, D and E are the mid points of the line segments AB and BC respectively.

Therefore, By mid point theorem,

coordinate of D are (\frac{2+6}{2} , \frac{2+8}{2} ) = (\frac{8}{2} , \frac{10}{2} )= (4,5)

Coordinate of E are  (\frac{2+8}{2} , \frac{2+4}{2} ) = (\frac{10}{2} , \frac{6}{2} )= (5,3)

By the distance formula,

DE=\sqrt{(5-4)^2+(3-5)^2}=\sqrt{5}

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By the slope formula,

Slope of AC = \frac{4-8}{8-6} = \frac{-4}{2} = -2

Slope of DE =  \frac{3-5}{5-4} = \frac{-2}{1} = -2


            Statement                                              Reason

1. The coordinate of D are (4,5)  and           1. By the midpoint formula

the coordinate of  E are (5,3)

2. The length of DE = √5                            2. By the Distance formula

The length AC = 2√5 ⇒ Segment DE

is half the length of segment AC

3. The slope of DE = -2 and the                3. By the slope formula

slope of AC = -2

4. DE║AC                                                   4. Slopes of parallel lines are equal


7 0
3 years ago
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The price of gold is often reported per ounce. At the end of 2005, this price was $513. At the end of 2015, it was $1060. By wha
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Answer:106.63%.

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