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borishaifa [10]
3 years ago
8

How did business leaders in the late nineteenth century utilize vertical integration? a. They maintained control of the raw mate

rials necessary for their products. b. They delegated responsibility for production and distribution to subsidiaries. c. They maintained control of production and distribution of their products. d. They allowed market forces to dictate how their products were distributed.
Mathematics
1 answer:
bulgar [2K]3 years ago
3 0

Business leaders in the late nineteenth century utilized vertical integration by maintaining control of production and distribution of their products.

Answer: Option C

<u>Explanation: </u>

Vertical integration is a competitive strategy that gives the company full control over one or more stages of product production or distribution. Rockefeller tirelessly tried to take full control of business 'oil refinery'. While other business people were flooding the area in search of quick fortune, Rockefeller was thinking of destroying his rivals and creating a real monopoly in the refining industry.

Looking for even more control, Rockefeller saw the benefits of organizing the transportation to his products. Then, he began to develop his business through vertical integration, in which the company analyses all aspects of the product life cycle, from raw material extraction, through the production process, to the final delivery of the product.

Other industrialists quickly followed, including Gustavus Swift, who at the end of the 19th century used vertical integration to dominate the American meat packaging industry.

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Richie and bethany play basketball and practice shooting free throws after school. During one practice session, Richie attempted
mamaluj [8]

Answer:

<em>Bethany did not do better than Richie because her average score was less than his.</em>

Step-by-step explanation:

<u>Average Value</u>

The average or mean value of m successes out of n tries is given by:

\displaystyle \bar x=\frac{m}{n}

During a practice session playing basketball, Richie made m=12 free throws from n=15 attempts. His average score was:

\displaystyle \bar x=\frac{12}{15}=0.8

Bethany made 8 free throws for every 3 that she missed, this means she made 8 out of 11 attempts. Her average score was:

\displaystyle \bar x=\frac{8}{11}=0.72

Bethany did not do better than Richie because her average score was less than his.

5 0
3 years ago
Suppose the probability of an IRS audit is 1.5 percent for U.S. taxpayers who file form 1040 and who earned $100,000 or more.
sp2606 [1]

Answer:

(A) The odds that the taxpayer will be audited is approximately 0.015.

(B) The odds against these taxpayer being audited is approximately 65.67.

Step-by-step explanation:

The complete question is:

Suppose the probability of an IRS audit is 1.5 percent for U.S. taxpayers who file form 1040 and who earned $100,000 or more.

A. What are the odds that the taxpayer will be audited?

B. What are the odds against such tax payer being audited?

Solution:

The proportion of U.S. taxpayers who were audited is:

P (A) = 0.015

Then the proportion of U.S. taxpayers who were not audited will be:

P (A') = 1 - P (A)

        = 1 - 0.015

        = 0.985

(A)

Compute the  odds that the taxpayer will be audited as follows:

\text{Odds of being Audited}=\frac{P(A)}{P(A')}

                                    =\frac{0.015}{0.985}\\\\=\frac{3}{197}\\\\=0.015228\\\\\approx 0.015

Thus, the odds that the taxpayer will be audited is approximately 0.015.

(B)

Compute the odds against these taxpayer being audited as follows:

\text{Odds against Audited}=\frac{P(A')}{P(A)}

                                    =\frac{0.985}{0.015}\\\\=\frac{3}{197}\\\\=65.666667\\\\\approx 65.67

Thus, the odds against these taxpayer being audited is approximately 65.67.

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