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Kryger [21]
2 years ago
12

Equation Unbalanced : __AlCl3 + __F2 --> __AlF3 + __Cl2

Chemistry
1 answer:
Greeley [361]2 years ago
6 0

\\ \rm\Rrightarrow 2AlCl_3+3F_2\longrightarrow 2AlF_3+3Cl_2

  • Balanced

3mols of fluorine produce 2 mol chlorine

1 mol fluorine produces 2/3=0.6mol chlorine

Moles of fluorine gas=

  • 4/19
  • 0.2mol.approx

Moles of chlorine:-

  • 0.2(0.6)=0.18mol

Mass of chlorine

  • 71(0.18)
  • 12.78g
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You notice that the water in your friend's swimming pool is cloudy and that the pool walls are discolored at the water line. A q
Flauer [41]

Answer:

6,78 mL of 12,0 wt% H₂SO₄

Explanation:

The equilibrium in water is:

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The initial concentration of [H⁺] is 10⁻⁸ M and final desired concentration is [H⁺] = 10^{-7,20}, thus,

Thus, you need to add:

[H⁺] = 10^{-7,2} -10^{-8,0} = 5,31x10⁻⁸ M

The total volume of the pool is:

9,00 m × 15,0 m ×2,50 m = 337,5 m³ ≡ 337500 L

Thus, moles of H⁺ you need to add are:

5,31x10⁻⁸ M × 337500 L = 1,792x10⁻² moles of H⁺

These moles comes from

H₂SO₄ → 2H⁺ +SO₄²⁻

Thus:

1,792x10⁻² moles of H⁺ × \frac{1H_{2}SO_4 mol}{2H^{+} mol} = 8,96x10⁻³ moles of H₂SO₄

These moles comes from:

8,96x10⁻³ moles of H₂SO₄ × \frac{98,1 g}{1 mol} × \frac{100 gSolution}{12 gH_{2}SO_4 } × \frac{1 mL}{1,080 g}  =

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I hope it helps!

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<span>Since,
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Answer:

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