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wel
2 years ago
8

Titration Lab Day 2 Data Sheet help?

Chemistry
1 answer:
igomit [66]2 years ago
6 0
Unfortunately, you haven't shared any data list which would make braunly users able to help you. The only thing I can suggest you is to write  the neutralization reactions, this can make you  understand the calculations more or less clearly. Please, next time check your attachments carefully.
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Created from the ...... of ..... in layers over long periods of time
Setler79 [48]
Sedimentary rocks. Not sure though
8 0
3 years ago
what is the molecular formula for a compound that is 39.99% carbon, 6.73% hydrogen, and 53.28% oxygen and has a molar mass of 18
4vir4ik [10]

Answer:

IDEK

Explanation:

5 0
2 years ago
Using the perodic table determine the number of protons for the element Li​
wolverine [178]
Answer is 3

because on the periodic table, the small number above every element is the number of protons
8 0
3 years ago
Some oxygen gas takes up a volume of 2.00 liters at 0.99 atm and 273 K. Its volume doubles and its temperature decreases to 137
nataly862011 [7]

Answer:

The answer to your question is : letter B. 0.25 atm

Explanation:

To solve this problem we need to use the combined gas law:

    <u>P₁V₁</u>   =    <u>P₂V₂</u>

      T₁              T₂

Data

P1 = 0.99 atm  V1 = 2 l  T1 = 273K

P2 = ?               V2 = 4 l   T2 = 137K

Now, the clear P2 from the equation and we get

       P2 = P1V1T2 / T1V2

Substitution         P2 = (2 x 0.99 x 137)/(273 x 4)

       P2 = 271.26 / 1092

Result       P2 = 0.248 atm ≈ 0.25 atm

5 0
3 years ago
Read 2 more answers
During chemical weathering, forsterite is dissolved by the carbonic acid in rainwater. The weathering reaction is as follows:
Semenov [28]

Answer:

Keqq = 310

Note: Some parts of the question were missing. The missing values are used in the explanation below.

Explanation:

<em>Given values: ΔH° = -178.8 kJ/mol = -178800 J/mol; T = 25°C = 298.15 K; ΔS° = -552 J/mol.K; R = 8.3145 J/mol.K</em>

Using the formula ΔG° = -RT㏑Keq

㏑Keq = ΔG°/(-RT)

where ΔG° = ΔH° - TΔS°

㏑Keq = ΔH° - TΔS°/(-RT)

㏑Keq = {-178800 - (-552 * 298.15)} / -(8.3145 * 298.15)

㏑Keq = -14221.2/-2478.968175

㏑Keq = 5.73674166

Keq = e⁵°⁷³⁶⁷⁴¹⁶⁶

Keq = 310.05

4 0
3 years ago
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