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wel
3 years ago
8

Titration Lab Day 2 Data Sheet help?

Chemistry
1 answer:
igomit [66]3 years ago
6 0
Unfortunately, you haven't shared any data list which would make braunly users able to help you. The only thing I can suggest you is to write  the neutralization reactions, this can make you  understand the calculations more or less clearly. Please, next time check your attachments carefully.
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A 100.0-g sample of water at 27.0oC is poured into a 71.0-g sample of water at 89.0oC. What will be the final temperature of the
Sedbober [7]

<u>Answer:</u> The final temperature will be 52.74^oC

<u>Explanation:</u>

Calculating the heat released or absorbed for the process:

q=m\times C\times (T_2-T_1)

In a system, the total amount of heat released is equal to the total amount of heat absorbed.

q_1=-q_2

OR

m_1\times C\times (T_f-T_1)=-m_2\times C\times (T_f-T_2) ......(1)

where,

C = heat capacity of water = 4.184J/g^oC

m_1 = mass of water of sample 1 = 100.0 g

m_2 = mass of water of sample 2 = 71.0 g

T_f = final temperature of the system = ?

T_1 = initial temperature of water of sample 1 = 27^oC

T_2 = initial temperature of the water of sample 2 = 89.0^oC

Putting values in equation 1, we get:

100.0\times 4.184\times (T_f-27)=-71.0\times 4.184\times (T_f-89)\\\\171T_f=9019\\\\T_f=\frac{9019}{171}=52.74^oC

Hence, the final temperature will be 52.74^oC

6 0
3 years ago
Cho phản ứng hóa học xảy ra theo phương trình sau: Al + HNO3 ® Al(NO3)3 + N2O + H2O. Sau phản ứng thu được 3,36 (l) khí N2O (đkc
Amanda [17]

Explanation:

my God what kinda learning you doing?

3 0
3 years ago
Student took 1.52ml of a stock CuSO4 solution, with a given concentration of 3.26mg/ml. He then added water to the solution unti
Bumek [7]

To solve this we use the equation, 

M1V1 = M2V2

where M1 is the concentration of the stock solution, V1 is the volume of the stock solution, M2 is the concentration of the new solution and V2 is its volume.

<span>3.26 x 1.52 = 13.26 x M2</span>

<span>M2 = 0.37 mg/mL</span>

4 0
3 years ago
Which particle has the same electron configuration as a potassium ion?
mars1129 [50]

Answer is D - Argon atom


Potassium has atomic number as 19. Hence, number of protons = 19

If the atom is neutral,

number of protons = number of electrons = 19


Hence, the electron configuration of potassium (K) is

1s² 2s² 2p⁶ 3s² 3p⁶ 4s¹


Potassium ion is formed by losing an electron. Then the number of electrons = 19 - 1 = 18


Electron configuration of K⁺ is 1s² 2s² 2p⁶ 3s² 3p⁶.


This is same as the electron configuration of Ar which has 18 electrons.

6 0
3 years ago
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Discuss sucrose transport in vascular plants
Xelga [282]

Answer:Sugars are actively transported from source cells into the sieve-tube companion cells, which are associated with the sieve-tube elements in the vascular bundles. ... The co transport of a proton with sucrose allows movement of sucrose against its concentration gradient into the companion cells.

Explanation:

4 0
3 years ago
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