Answer:

Step-by-step explanation:
Hello,
a and b are the zeros, we can say that

So we can say that

Now, we are looking for a polynomial where zeros are 2a+3b and 3a+2b
for instance we can write

and we can notice that
so
![(x-2a-3b)(x-3a-2b)=x^2-5(a+b)x+6[(a+b)2-2ab]+13ab\\= x^2-5(a+b)x+6(a+b)^2+ab](https://tex.z-dn.net/?f=%28x-2a-3b%29%28x-3a-2b%29%3Dx%5E2-5%28a%2Bb%29x%2B6%5B%28a%2Bb%292-2ab%5D%2B13ab%5C%5C%3D%20x%5E2-5%28a%2Bb%29x%2B6%28a%2Bb%29%5E2%2Bab)
it comes

multiply by 3

Answer: C
Step-by-step explanation:

Answer:
By themselves $18.20, $13.60, and together $31.80
Step-by-step explanation:
$2.60 multiplied by 7 equals $18.20
$3.40 multiplied by 4 equals $13.60
Together this equals $31.80
15x - 5(3x-7) = 14
15x - 15x+ 35 = 14
35 = 14 ...NOT TRUE
answer
NO solution
you got it correct
Answer:
y=1
Step-by-step explanation: