There are two ways to do this.
The first is you plug in the x-value from the point in the table and see if that gives you the y-value from the same point.
For example, your first point is (5,49), so plug in x=5:
y = -5(5)+2 = -25+2 = -23
Since that's not the y-value in (5,49), then (5,49) is not a solution for the equation.
The other option is you plug in both the x-value and the y-value to see if you get a true statement. (A solution will make the equaiton a true statement.)
For example, the first point is (5,49), so you'd plug in x=5 and y=49:
49 = -5(5)+2
49 = -25 + 2
49 = -23
Since that's not true, (5,49) is not a solution.
You'll notice you're basically doing the same thing, it's just whether you plug in one value or both and that's your choice.
8 is your answe have a nice day
Answer:
864
Step-by-step explanation:
A=6a^2=6·12^2=864
I haven't done proofs in a while, but one thing that might help is that only if two lines were parallel would angles 3 and 1 be congruent (3 is congruent to 2, which is congruent to 1, so they're all congruent to each other).
The median average refers to number in the middle of the set. But we need to write it in chronological order.
Now the set becomes 57, 60, 62, 65.
Now find the number in the middle. In this case, it both 60 and 62.
But we need one number.
So, we will take the average of both of them.
60 + 62 = 122
122 / 2 = 61
So, 61 is the median of the set.
EDIT:
Big thanks to mkersten for finding two errors in my answer!
