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2 years ago

Please Help Me Will Give Brainliest AYUDA

Mathematics

2 answers:

zvonat [6]2 years ago

8 0

Answer:

Option A is right

Step-by-step explanation:

In any data set, we find that the range is the difference between maximum and minimum. The range cannot give full information about the variability of the data set.

Outliers are the ones which are either below Q1-1.5IQR or Q3+1.5IQR

Thus Inter quartile range, the difference between I quartile and III quartile gives a better idea about variability and also outlier.

Hence out of the four options given, we find that option B is the right one.

Option

A. The IQR is the best measure of variability because the distribution has an outlier.

NikAS [45]2 years ago

3 0

Answer: the answer is a

Step-by-step explanation: hope it is correct .

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2 years ago

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3 years ago

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3 years ago

Jack is flying his kite . He runs 100 feet away from his house and lets out 45 feet of string . The angle of elevation from the

fiasKO [112]

Answer: 125.80 ft

Step-by-step explanation:

Asuming the described situation is as shown in the figure below, we need to find the distance $h$ between the kite and Jacks house, but first we need to find the $x$ , $y$ and then $d$ .

How?

We will use trigonometry, especifically the trigonometric functions sine and cosine:

For $y$ :

$sin(65 \°)=\frac{y}{45 ft}$ (1)

Where $y$ is the opposite side to the angle and $45 ft$ the hypotenuse.

Isolating $y$ :

$y=40.78 ft$ (2)

For $x$ :

$cos(65 \°)=\frac{x}{45 ft}$ (3)

Where $x$ is the adjacent side to the angle.

Isolating $x$ :

$y=19.017 ft$ (4)

Finding $d$ :

$d=x+100 ft$ (5)

$d=19.017 ft +100 ft$

$d=119.017 ft$ (6)

Now that we have found these values, we have to work with a bigger triangle, where the hypotenuse is the distance between the kite and Jack's house $h$ and the sides are the values calculated in (4) and (6).

So, in this case we will use the <u>Pithagorean theorem</u>:

$h^{2}=y^{2} +d^{2}$ (7)

Isolating $h$ and writing with the known values:

$h=\sqrt{y^{2} +d^{2}}$ (8)

$h=\sqrt{(19.017 ft)^{2} +(119.017 ft)^{2}}$ (9)

$h=125.80 ft$ This is the distance between the kite and the house

3 0

3 years ago