The amount of Cute Puppy food needed for the year is 1140 cans.
<h3>Determining the total number of cans that the dogs eat in a year</h3>
The first step in determining the total number of cans needed in year is to calculate the sum of dog food consumed in a week.
8.25 + 15.5 = 23.75 cans
The second step is to determine the total cans the dogs consume in a month
23.75 x 4 = 95
The third second step is to determine the total cans the dogs consume in a year:
95 x 12 = 1140 cans
<h3>Cost of cute puppy food needed in a year</h3>
1140 x ($21 /40) = $598.50
To learn more about addition, please check: brainly.com/question/19628082
Theoretical Probability is what you think the result will be, and experimental probability is what it turns out to be, hope this helps.
Answer:
13 ft/s
Step-by-step explanation:
t seconds after the boy passes under the balloon the distance between them is ...
d = √((15t)² +(45+5t)²) = √(250t² +450t +2025)
The rate of change of d with respect to t is ...
dd/dt = (500t +450)/(2√(250t² +450t +2025)) = (50t +45)/√(10t² +18t +81)
At t=3, this derivative evaluates to ...
dd/dt = (50·3 +45)/√(90+54+81) = 195/15 = 13
The distance between the boy and the balloon is increasing at the rate of 13 ft per second.
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The boy is moving horizontally at 15 ft/s, so his position relative to the spot under the balloon is 15t feet after t seconds.
The balloon starts at 45 feet above the boy and is moving upward at 5 ft/s, so its vertical distance from the spot under the balloon is 45+5t feet after t seconds.
The straight-line distance between the boy and the balloon is found as the hypotenuse of a right triangle with legs 15t and (45+5t). Using the Pythagorean theorem, that distance is ...
d = √((15t)² + (45+5t)²)
Answer:
6% monthly
Step-by-step explanation:
The monthly rate being compounded when the interest is 6% per year is ...
6%/12 = 0.5%
so the multiplier each month is
1 + 0.5% = 1.005
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The monthly multiplier when 5.86% is compounded continuously is ...
e^(5.86%/12) ≈ 1.004895
The 6% rate will give a larger yield after any length of time.
A. Reflection over y = 2
B. Reflection over y axis, reflection over y = 1
C. I'm guessing you just have to draw this one, just put the center on (2,0) and enlarge it by the scale factor
