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adoni [48]
2 years ago
12

Make f the subject of 12k^2 = root (f+6)/2

Mathematics
1 answer:
adell [148]2 years ago
7 0

Answer:

f=2×12k⁴-6

Step-by-step explanation:

root(f+6/2)=12k²

take the root away f+6/2=12k²

f+6/2=12k⁴

f=2×12k⁴-6

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Determine the product.
Andrei [34K]

The final expression in standard form will be 1.601 * 10^9

<h3>Indices and expoenets</h3>

Given the expression as shown:

800.5 * (2*10^6)

This can be further simplified as:

=  8.005 * 10 ^2 * 2 * 10^6\\= 16.01 * 10^{2+6}\\= 16.01 * 10^8

The final expression in standard form will be 1.601 * 10^9

Learn more on indices here: brainly.com/question/10339517

3 0
2 years ago
Read 2 more answers
I need help on listing the four points that have a distance of 8 from B, thank you!
dolphi86 [110]

Answers:

  • (12, 3)
  • (-4, 3)
  • (4, 11)
  • (4, -5)

A diagram is shown below.

===========================================================

Explanation:

First we locate point B at (4,3). The '4' in the x position means we've gone 4 units to the right of the origin, and the 3 in the y coordinate means we've gone 3 units up.

Now we need to find four points that are 8 units away from this central location. We'll ignore point A.

What we can do is add 8 to the x coordinate of point B to get x+8 = 4+8 = 12. Keeping the y coordinate the same, the point (12, 3) is exactly 8 units away from (4,3). Think of drawing a number line through those two points. Then we can note there are 8 spaces between (4,3) and (12,3). Or we can say "there are 8 spaces between 4 and 12" since that '3' doesn't really play much of a role in this case.

So (12,3) is one answer.

---------------------------------

Move back to point B(4,3)

Instead of adding 8 to the x coordinate, let's subtract 8 from it

x-8 = 4-8 = -4

Again the y coordinate is kept the same.

The point (-4, 3) is 8 units away from (4,3). The number line distance from -4 to 4 is 8 units.

So (-4,3) is another answer.

----------------------------------

Move back to point B

From this starting point, we can move 8 units up. Doing this means we add 8 to the y coordinate, while the x coordinate is kept intact.

(4,3) turns into (4,11) after doing so.

(4,11) is another answer.

---------------------------------

Move back to point B

From this point, we can move down 8 units to arrive at (4,-5). note how y-8 = 3-8 = -5. The x coordinate is kept the same.

(4,-5) is another answer.

----------------------------------

The four points we found were:

  • (12, 3)
  • (-4, 3)
  • (4, 11)
  • (4, -5)

which are four possible answers

Those points are found by going 8 units right, 8 units left, 8 units up and 8 units down in that order. Each time we started at point B as our center of operation. The use of the word "center" is done because we can form a circle of radius 8, and the center of the circle is at B(4,3). Any point on the circle's edge is exactly 8 units away from the center point B.

Refer to the diagram below. The four answers are the red points P,Q,R,S. The point T is another point that could be an answer, but it's not as easy to find compared to the four other points.

3 0
3 years ago
UGHHHH PLZ HELP !!!hate usa test prep
zloy xaker [14]
The answer is 1 computer/8 students
8 0
3 years ago
Read 2 more answers
Simplify this expression<br> (5x+2)^2
Galina-37 [17]

[ Answer ]

\boxed{25x^2 \ + \ 20x\ + \ 4}

[ Explanation ]

  • Simplify: (5x \ + \ 2)^{2}

------------------------------------------

  • Apply Perfect Square Formula ((a \ + \ b)^{2} = a^{2} + 2ab + b^{2}) a = 5x, b = 2

(5x)^{2} + 2 · 5x · 2 + 2^{2}: 25x^{2} + 20x + 4

  • Answer

25x^{2} + 20x + 4

\boxed{[ \ Eclipsed \ ]}

5 0
3 years ago
How do I find the center &amp; radius, then write a standard equation for a,b, and c?
Ghella [55]

Firstly , we will locate centres and radius in the figures

(a)

We can see that

centre=(h,k)=(0,0)

radius=r=5

now, we can use standard equation of circle

(x-h)^2+(y-k)^2=r^2

we can plug values

we get

(x-0)^2+(y-0)^2=5^2

x^2+y^2=25

(b)

We can see that

centre=(h,k)=(5,4)

radius=r=3

now, we can use standard equation of circle

(x-h)^2+(y-k)^2=r^2

we can plug values

we get

(x-5)^2+(y-4)^2=3^2

(x-5)^2+(y-4)^2=9

(c)

We can see that

centre=(h,k)=(4,3)

radius=r=5

now, we can use standard equation of circle

(x-h)^2+(y-k)^2=r^2

we can plug values

we get

(x-4)^2+(y-3)^2=5^2

(x-4)^2+(y-3)^2=25


5 0
3 years ago
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