Answer:
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Step-by-step explanation:
Y=2 x=3 double check is at bottom but cut off
F: R → R is given by, f(x) = [x]
It is seen that f(1.2) = [1.2] = 1, f(1.9) = [1.9] = 1
So, f(1.2) = f(1.9), but 1.2 ≠ 1.9
f is not one-one
Now, consider 0.7 ε R
It is known that f(x) = [x] is always an integer. Thus, there does not exist any element x ε R such that f(x) = 0.7
So, f is not onto
Hence, the greatest integer function is neither one-one nor onto.
The answer was quite complicated but I hope it will help you.
Answer:
W=4h(11-j)/b-h
Step-by-step explanation:
Eliminate variables on the left side first.
b(h+w) = 4h (11-j) - so, divide b by both sides
(h+w)/b=4h(11-j)/b then, eliminate h by subtracting on both sides.
(h+w)-h=4h(11-j)/b - h (h is eliminated on the left side and now you are left with
W=4h(11-j)/b - h
-4/5 = -16/20, so the new expression is (-16/20)+(3/20)
then, -16 + 3 is -13, so the solution is -13/20
