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Ainat [17]
2 years ago
8

Write an equation for each graph:

Mathematics
1 answer:
Amiraneli [1.4K]2 years ago
4 0

Answer:

y=-|x+1|+1

Step-by-step explanation:

Parent function:  y=|x|

Reflect in the x-axis:  y=-|x|

Translate 1 unit to the left:  y=-|x+1|

Translate 1 unit up:  y=-|x+1|+1

Please refer to the attachments to see the individual transformations.

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-15X - 40 = 23 - 8<br> This is the problem and I am totally lost
Elena-2011 [213]
-15x-40=15
then add 40 to both sides to get the constants on 1 side and variables on the other
-15x=25
now you just divide by -15
x = -1.67 or x = -1/3
3 0
3 years ago
Read 2 more answers
What’s x in the question
Lina20 [59]

Answer:

x = 5/(a+3-b)

Step-by-step explanation:

ax+3x = bx+5

ax+3x-bx = 5

Take x as a common.

x(a +3 - b) = 5

x = 5/(a+3-b)

4 0
3 years ago
Let ​ f(x)=x2+14x+36 ​ .
azamat

Answer:

see explanation

Step-by-step explanation:

The vertex form of f(x) is

f(x) = (x - h)² + k

where (h, k) are the coordinates of the vertex

To obtain this form use the method of completing the square

add/subtract ( half the coefficient of the x- term )² to x² + 14x

f(x) = x² + 2(7)x + 49 - 49 + 36

     = (x + 7)² - 13

The minimum value of f(x) is the y- coordinate of the vertex

vertex = (- 7, - 13), that is minimum value = - 13

6 0
4 years ago
Given: || EIJ GJI Prove: JIK IJL
EastWind [94]
Jk+jik+ijl goodluck :)

6 0
3 years ago
75% of all undergraduates are in the College, 10% are in Engineering, 8% are in Commerce, 4% are in Nursing, and 3% are in Archi
Hunter-Best [27]

Answer:

the probability a randomly selected student is a third-year that they are in the College is 0.1743

Step-by-step explanation:

Given information

75% College = C = 0.75

10% are in Engineering, Eng = 0.1

8% are in Commerce, Com = 0.08

4% are in Nursing, Nurs = 0.04

3% are in Architecture, Arch = 0.03

21% Third year student = S = 0.21

21% in the College = 0.21

25% in Engineering = 0.25

49% in Commerce = 0.49

57% in Nursing = 0.57

33% in Architecture = 0.33

P(SlC) = 0.75 x 0.21 = 0.1575 is the probability of third year student in college

P(SlEng) = 0.1 x 0.25 = 0.025

P(SlCom) = 0.08 x 0.49 = 0.0392

P(SlNurs) = 0.04 x 0.57 = 0.0288

P(SlArch) = 0.03 x 0.33 = 0.0099

P(S) = P(SlEng) + P(SlCom) + P(SlNurs) +P(SlArch)

       = 1- (0.025 + 0.0392 + 0.0288 + 0.0099)

       = 0.9031

The probability of third year student in college is

P(ClS) = P(SlC) / P(S)

           = 0.1575 / 0.9031

           = 0.1743

3 0
4 years ago
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