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ollegr [7]
1 year ago
14

This ven diagram shows sports played by 10 students.

Mathematics
1 answer:
grin007 [14]1 year ago
3 0
The answer is B because 4 x 5 is 20 times the amount of player 10
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A courtyard has three walls with widths
wariber [46]

Using the greatest common factor, it is found that the greatest dimensions each tile can have is of 3 feet.

---------------------------

  • The widths of the walls are of <u>27 feet, 18 feet and 30 feet.</u>
  • <u>The tiles must fit the width of each wall</u>, thus, the greatest dimension they can have is the greatest common factor of 27, 18 and 30.

To find their greatest common factor, these numbers must be factored into prime factors simultaneously, that is, only being divided by numbers of which all three are divisible, thus:

27 - 18 - 30|3

9 - 6 - 10

No numbers by which all of 9, 6 and 10 are divisible, thus, gcf(27,18,30) = 3 and the greatest dimensions each tile can have is of 3 feet.

A similar problem is given at brainly.com/question/6032811

8 0
3 years ago
Connecticut families were asked how much they spent weekly on groceries. Using the following data, construct and interpret a 95%
Amanda [17]

Answer:

The 95% confidence interval for the population mean amount spent on groceries by Connecticut families is ($73.20, $280.21).

Step-by-step explanation:

The data for the amount of money spent weekly on groceries is as follows:

S = {210, 23, 350, 112, 27, 175, 275, 50, 95, 450}

<em>n</em> = 10

Compute the sample mean and sample standard deviation:

\bar x =\frac{1}{n}\cdot\sum X=\frac{ 1767 }{ 10 }= 176.7

s= \sqrt{ \frac{ \sum{\left(x_i - \overline{x}\right)^2 }}{n-1} }       = \sqrt{ \frac{ 188448.1 }{ 10 - 1} } \approx 144.702

It is assumed that the data come from a normal distribution.

Since the population standard deviation is not known, use a <em>t</em> confidence interval.

The critical value of <em>t</em> for 95% confidence level and degrees of freedom = n - 1 = 10 - 1 = 9 is:

t_{\alpha/2, (n-1)}=t_{0.05/2, (10-1)}=t_{0.025, 9}=2.262

*Use a <em>t</em>-table.

Compute the 95% confidence interval for the population mean amount spent on groceries by Connecticut families as follows:

CI=\bar x\pm t_{\alpha/2, (n-1)}\cdot\ \frac{s}{\sqrt{n}}

     =176.7\pm 2.262\cdot\ \frac{144.702}{\sqrt{10}}\\\\=176.7\pm 103.5064\\\\=(73.1936, 280.2064)\\\\\approx (73.20, 280.21)

Thus, the 95% confidence interval for the population mean amount spent on groceries by Connecticut families is ($73.20, $280.21).

7 0
3 years ago
Please help im struggling on this ​
Ksivusya [100]

Answer:

It looks like you cut off part of the questions...

Step-by-step explanation:

8 0
2 years ago
-17-5(x+3)=3x plz help
katovenus [111]
  1. Start by distributing the -5 into the x and 3
  2. -17-5x-15=3x
  3. add like terms
  4. -5x-32=3x
  5. add 32 to both sides
  6. -5x=3x+32
  7. subtract 3x from both
  8. -8x=32
  9. divide both by -8
  10. x=-4

7 0
3 years ago
Read 2 more answers
The area of square is 36 square meters. what is the length (in meters) of one side in the square
expeople1 [14]

Answer:6m

Step-by-step explanation:

Square root 36m²

8 0
3 years ago
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