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2 years ago

This ven diagram shows sports played by 10 students.

Mathematics

1 answer:

grin007 [14]2 years ago

3 0

The answer is B because 4 x 5 is 20 times the amount of player 10

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Answer the statistical measures and create a box and whiskers plot for the following set of data.

suter [353]

Answer:

Minimum = 5

Lower Quartile (Q1) = 6

Median = 9

Upper Quartile (Q3) = 12

Maximum = 15

4 0

3 years ago

I give brainliest please help

Furkat [3]

It’s the 31 hope this helps you

3 0

3 years ago

Max and Sasha exercise a total of 20 hours each week. Max exercises 15 hours less than 4 times the

navik [9.2K]

Answer:

Max exercises 13 hours a week, and Sasha 7.

Step-by-step explanation:

To find the number of hours each of them exercises during the week, we solve the system of equations.

In the second equation:

$x = 4y - 15$

Replacing in the first equation:

$x + y = 20$

$4y - 15 + y = 20$

$5y = 35$

$y = \frac{35}{5}$

$y = 7$

So Sasha exercises 7 hours per week.

Max:

$x + y = 20$

$x + 7 = 20$

$x = 13$

Max exercises 13 hours a week.

6 0

3 years ago

Given that

MissTica

Answer:

-2

Step-by-step explanation:

Hey there!!

if we evaluate the expression it will look like :

3x + 14 = 8

and if we solve it:

3x+14=8

Step 1: Subtract 14 from both sides.

3x+14−14=8−14

3x=−6

Step 2: Divide both sides by 3.

3x/3 = -6/3

x= −2

4 0

3 years ago

A limnologist wishes to estimate the mean phosphate content per unit volume of lake water. It is knownfrom studies in previous y

telo118 [61]

Answer: 68

Step-by-step explanation:

As per given , we have

Population standard deviation : $\sigma=4$

Critical value for 90% confidence interval = $z_{\alpha/2}=1.645$

Margin of error : E= 0.8 milligrams

The formula to find the sample size is given by :-

$n=(\dfrac{z_{\alpha/2}\ \sigma}{E})^2$

i.e. $n=(\dfrac{(1.645)(4)}{0.8})^2=(8.225)^2$

$=67.650625\approx68$

Hence, the limnologist must analyze 68 samples.

6 0

3 years ago