All categories

2 years ago

Solve using quadratic formula pls show work

Mathematics

1 answer:

Temka [501]2 years ago

4 0

Answer:

$x=\frac{3}{8},\:x=0$

Step-by-step explanation:

$x_{1,\:2}=\frac{-\left(-3\right)\pm \sqrt{\left(-3\right)^2-4\cdot \:8\cdot \:0}}{2\cdot \:8}$

$\sqrt{\left(-3\right)^2-4\cdot \:8\cdot \:0}$

$=\sqrt{3^2-4\cdot \:8\cdot \:0}$

$\sqrt{3^2}$

$x_{1,\:2}=\frac{-\left(-3\right)\pm \:3}{2\cdot \:8}$

Separate the solutions:

$x_1=\frac{-\left(-3\right)+3}{2\cdot \:8},\:x_2=\frac{-\left(-3\right)-3}{2\cdot \:8}$

$x=\frac{3}{8},\:x=0$

You might be interested in

The stream of water from a fountain follows a parabolic path. The stream reaches a maximum height of 7 feet, represented by a ve

xenn [34]

First of all, I'm going to assume that we have a concave down parabola, because the stream of water is subjected to gravity.

If we need the vertex to be at $x=4$ , the equation will contain a $(x-4)^2$ term.

If we start with $y=-(x-4)^2$ we have a parabola, concave down, with vertex at $x=4$ and a maximum of 0.

So, if we add 7, we will translate the function vertically up 7 units, so that the new maximum will be $(4, 7)$

We have

$y = -(x-4)+7$

Now we only have to fix the fact that this parabola doesn't land at $(8,0)$ , because our parabola is too "narrow". We can work on that by multiplying the squared parenthesis by a certain coefficient: we want

$y = a(x-4)^2+7$

such that:

$a$
when we plug $x=8$ , we have $y=0$

Plugging these values gets us

$0 = a(8-4)^2+7 \iff 16a+7=0 \iff a = -\dfrac{7}{16}$

As you can see in the attached figure, the parabola we get satisfies all the requests.

3 0

3 years ago

I need help with 50. I don't know how to figure it out

Nikolay [14]

The answer is in the picture

8 0

3 years ago

Triangle CAT is transformed to produce triangle DOG.

PilotLPTM [1.2K]

Using transformations and congruency concepts, it is found that with these following transformations, the triangles will be congruent.

A reflection, then a translation.
A rotation, then a reflection.

--------------------------

Two triangles are congruent if they have the same lengths of the sides and the same angles.

In a reflection, there is a rule that changes the coordinates (x,y), but does not change the lengths of the sides of the triangles, thus they will still be congruent.
A reflection is also a special case of rotation, thus, in a rotation, the triangles are also congruent.
A translation is also similar to a reflection, using rules to shift the triangle up, down, left or right according to it's coordinates, not changing the sides or angles, thus congruent.
In a dilation, the lengths of the sides are changed, thus, the triangles will not be congruent.

--------------------------

Thus, from the bullet points above, the correct options are:

A reflection, then a translation.
A rotation, then a reflection.

A similar problem is given at brainly.com/question/24267298

3 0

3 years ago

Solve the following equations for x x(14-x) = 33

Katarina [22]

ANSWER :

14x-x^2 = 33

Step-by-step explanation:

x(14-x) = 33

14x-(x)^2 = 33

7 0

3 years ago

Sarah can take no more than 22 pounds and I like the trap her suitcase weighs 112 ounces how many more pounds can she park witho

Leya [2.2K]

Answer:

15 pounds

Step-by-step explanation:

there are 16 ounces in one pound

so...

first find the limit in ounces

$22 = \frac{x}{16}$

because there are 16 ounces in every one pound you need to multiply 22 by 16

which is 352

now subtract what you already used

$352 - 112$

which is 240

now convert to pounds

$x = \frac{240}{16}$

which is 15

so 15 more pounds

3 0

3 years ago

Solve using quadratic formula pls show work​

Solve using quadratic formula pls show work