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3 years ago

Please help me please i really need help please

Mathematics

2 answers:

vladimir2022 [97]3 years ago

4 0

Answer:

x= -6

y= -5

Step-by-step explanation:

(x,y) = (-6, -5)

velikii [3]3 years ago

4 0

Answer:

(-6,-5)

x=-6

y=-5

Step-by-step explanation:

9x-7y=-19

5x-3y=-15

When solving with elimination, you multiply both equations by a number to get two terms to cancel each other out.

We can try to get the y's to cancel out. The LCD of 7 and 3 is 21, so we multiply one equation by 3 and another by -7 (to get one -21y and one 21y)

{9x-7y=-19}*3=

27x-21y=-57

{5x-3y=-15}*(-7)=

-35x+21y=105

Now, we combine the two equations.

27x-21y=-57

-35x+21y=105

-8x=48

Now, solve for x.

-8x=48

x=-6

Now we can plug x into one of the original equations to get y.

I will use 9x-7y=-19.

9(-6)-7y=-19

-54-7y=-19

Add 54 to both sides.

-7y=35

y=-5

We can put these values into an ordered pair: (-6,-5).

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3 years ago

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astraxan [27]

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4 0

3 years ago

Read 2 more answers

6. If the net investment function is given by

Pachacha [2.7K]

The capital formation of the investment function over a given period is the

accumulated capital for the period.

(a) The capital formation from the end of the second year to the end of the fifth year is approximately 298.87.

(b) The number of years before the capital stock exceeds $100,000 is approximately 46.15 years.

Reasons:

(a) The given investment function is presented as follows;

$I(t) = 100 \cdot e^{0.1 \cdot t}$

(a) The capital formation is given as follows;

$\displaystyle Capital = \int\limits {100 \cdot e^{0.1 \cdot t}} \, dt =1000 \cdot e^{0.1 \cdot t}} + C$

From the end of the second year to the end of the fifth year, we have;

The end of the second year can be taken as the beginning of the third year.

Therefore, for the three years; Year 3, year 4, and year 5, we have;

$\displaystyle Capital = \int\limits^5_3 {100 \cdot e^{0.1 \cdot t}} \, dt \approx 298.87$

The capital formation from the end of the second year to the end of the fifth year, C ≈ 298.87

(b) When the capital stock exceeds $100,000, we have;

$\displaystyle \mathbf{\left[1000 \cdot e^{0.1 \cdot t}} + C \right]^t_0} = 100,000$

Which gives;

$\displaystyle 1000 \cdot e^{0.1 \cdot t}} - 1000 = 100,000$

$\displaystyle \mathbf{1000 \cdot e^{0.1 \cdot t}}} = 100,000 + 1000 = 101,000$

$\displaystyle e^{0.1 \cdot t}} = 101$

$\displaystyle t = \frac{ln(101)}{0.1} \approx 46.15$

The number of years before the capital stock exceeds $100,000 ≈ 46.15 years.

Learn more investment function here:

brainly.com/question/25300925

6 0

2 years ago

Complete the blank with either ∈ or ∉ so that the resulting statement is true. −2__{−6,−3,−5,−1}

Misha Larkins [42]

Answer:

−2 ∉ {−6,−3,−5,−1}

Step-by-step explanation:

Given

Set = {−6,−3,−5,−1}

Element = -2

Required

The interpretation of the question is to state if -2 is an element of the given set or not

The first thing to do is to check through the set to count the number of occurrence of -2

Looking through Set = {−6,−3,−5,−1}, we have that the occurrence of -2 is 0

This implies that -2 is not an element of the given set and this is represented by the symbol ∉

Hence:

−2 ∉ {−6,−3,−5,−1}

7 0

3 years ago