Question

1+log2=log(x+1) I know that x=19 but how do you get 19?

Answer 1

Step-by-step explanation:

Recall that $\log 10 = 1$ so we can rewrite the equation above as

$\log 10 + \log 2 = \log (x + 1)$

Also recall that $\log(ab) = \log a + \log b$ so the left-hand side becomes

$\log [(10)(2)] = \log (x + 1)$

or

$20 = x + 1 \Rightarrow x = 19$