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oksian1 [2.3K]
3 years ago
5

1+log2=log(x+1) I know that x=19 but how do you get 19?

Mathematics
1 answer:
ycow [4]3 years ago
4 0

Step-by-step explanation:

Recall that \log 10 = 1 so we can rewrite the equation above as

\log 10 + \log 2 = \log (x + 1)

Also recall that \log(ab) = \log a + \log b so the left-hand side becomes

\log [(10)(2)] = \log (x + 1)

or

20 = x + 1 \Rightarrow x = 19

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Answer:

option b)

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Step-by-step explanation:

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Given in the questions are some pythagorus identities which except of b) are all incorrect as explained below.

<h3>1)</h3>

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4 0
3 years ago
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3 years ago
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