1+log2=log(x+1)
I know that x=19 but how do you get 19?
1 answer:
Step-by-step explanation:
Recall that
so we can rewrite the equation above as
![\log 10 + \log 2 = \log (x + 1)](https://tex.z-dn.net/?f=%5Clog%2010%20%2B%20%5Clog%202%20%3D%20%5Clog%20%28x%20%2B%201%29)
Also recall that
so the left-hand side becomes
![\log [(10)(2)] = \log (x + 1)](https://tex.z-dn.net/?f=%5Clog%20%5B%2810%29%282%29%5D%20%3D%20%5Clog%20%28x%20%2B%201%29)
or
![20 = x + 1 \Rightarrow x = 19](https://tex.z-dn.net/?f=20%20%3D%20x%20%2B%201%20%5CRightarrow%20x%20%3D%2019)
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