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Vlad [161]
2 years ago
13

Can you just answer question 23!!! i need help!!!

Mathematics
1 answer:
Veseljchak [2.6K]2 years ago
4 0

Answer:

It is Graph A because it has the properties of a cubic graph.

please mark as brainliest thank you

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Four and one-half minus three and five-eighths
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4 1/2-3 5/8=0.875 or 875/1000 or 35/40 or 7/8
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3 years ago
Figure out what the percent is
DaniilM [7]

The percentage of data that is roughly greater than 66, as displayed in the box plot, is 100%.

<h3>How to Determine a Percentage of a Data Represented in a Box Plot?</h3>

In a box plot, we have the following displayed five-number summary which tells what percentage of the data distribution for each part of the data distribution:

Upper quartile (Q3): This is the value at where the box in the box plot ends at the edge of the box. From this point to the left, all data values that fall within the bracket make up 75% of the data.

Lower quartile (Q3): This is the value at where the box in the box plot starts at the edge of the box. From this point to the left, all data values that fall within the bracket make up 25% of the data.

Median: this is the middle value at the point where the line divides the box and data below this point make up 50% of the data.

The other five-number summary are the maximum and the minimum values that are represented by the whiskers.

On the box plot given, 66 is at the extreme whisker at the left. This means that the percentage of data that is roughly greater than 66 is 100%.

Learn more about the box plot on:

brainly.com/question/14277132

#SPJ1

7 0
1 year ago
What is the smallest number by which 256 may be divided so that the quotient is perfect cube? (A) 2 (B) 3 (C) 4
densk [106]

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A.2

Step-by-step explanation:

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Graph the image of F(-8, 10) after a rotation 180° counterclockwise around the origin.
pychu [463]

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Step-by-step explanation:

clockwise or counter-clockwise do not matter when the rotation is 180°

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4/3 (4•5)} = 203 <br><br> ? = 203
Marta_Voda [28]

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4/3 (4•5)} = 203

Step-by-step explanation:

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