The measure off DF is 11.
In a circle inscribed within a triangle, the distance from each vertex of the triangle to the two nearest touchpoints (points of tangency on the circle) are equal. Since SD=4, DT=4 as well. Since UF=7, then FT=7.
DF=DT+TF=4+7=11.
Answer:
y=5(x-3)^2+2
Step-by-step explanation:
You plug the point into f(x)=a(x-3)^2+2... that already has already been solved for the vertex that you want. Then you swap it out for the solution you have solved for.
Answer:Hi Step-by-step explanation:
