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2 years ago

6

A rocket is launched from the top of a 70 foot cliff with an initial velocity of 130 feet per second. The height, h, of the rock

et after t seconds is given by the equation
h=-161² +130t+70. How long after the rocket is launched will it be 30 feet from the ground?

1 answer:

lana [24]2 years ago

6 0

Answer:

The answer is 7.8 seconds.

Solve for t in the equation using the Quadratic formula.
Eliminate the negative solution and the positive solution is your answer.

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