Question

A rocket is launched from the top of a 70 foot cliff with an initial velocity of 130 feet per second. The height, h, of the rocket after t seconds is given by the equation
h=-161² +130t+70. How long after the rocket is launched will it be 30 feet from the ground?

Answer 1

Answer:

The answer is 7.8 seconds.

1. Solve for t in the equation using the Quadratic formula.
2. Eliminate the negative solution and the positive solution is your answer.

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