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Alexandra [31]
3 years ago
15

The coordinate plane below represents a town. Points A through F are farms in the town.

Mathematics
1 answer:
Fiesta28 [93]3 years ago
6 0

Part A)

You can isolate Point E , by drawing a solid horizontal line at Y4, which be be the equation: y ≥ 4

Then in order to isolate point D you need an angles line, since you already have a horizontal line at Y 4 use this as the Y intercept, which would mean the point is (0,4) give the line a slope of 1 and you can reverse the first point to get the other point ( -4, 0), this will be a solid line to include the y intercept of 4:

This equation would be: y ≥ x + 4


Now see attached picture showing the two lines and shaded area would include D and E


Part B)

To verify D and E are solutions, find their X and Y coordinates:

D is at (-4,2)

So looking at the second equation from Part A replaxe x with -4: y = -4 + 4 = 0 and the Y is 2, which is greater tah 0, so D is a solution.

E is at (-1,5) and using the first equation from Part A, 5 is greater than 4, so this is also a solution.


Part C)

You can give X a number and solve for Y. Do this twice to create 2 points, then you can draw a line connecting the two points to see which farms you can have chickens on.

At X 0, Y > -4, so your first point is (0,-4)

At X 1, Y> -1, your second point is (1,-1)

See the second picture with just the red shaded area. Any farm located in that area can raise chickens.



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Here are yesterday's high temperatures (in Fahrenheit) in 12 U.S. cities. 48, 50, 54, 56, 63, 63, 64, 68, 74, 74, 79, 80 Notice
irinina [24]

For the given data set

Minimum = 48

Lower quartile = 55

Median = 63.5

Upper quartile = 74

Maximum = 80

Interquartile range = 19

<h3>Measures of a Data </h3>

From the question, we are to determine the minimum, lower quartile, median, upper quartile, maximum, and interquartile range of the given data set

The given data set is

48, 50, 54, 56, 63, 63, 64, 68, 74, 74, 79, 80

Minimum = 48

Lower quartile = (54+56)/2

Lower quartile = 110/2

Lower quartile = 55

Median = (63+64)/2

Median = 127/2

Median = 63.5

Upper quartile = (74+74)/2

Upper quartile = 148/2

Upper quartile = 74

Maximum = 80

Interquartile range = Upper quartile - Lower quartile

Interquartile range = 74 - 55

Interquartile range = 19

Hence, for the given data set

Minimum = 48

Lower quartile = 55

Median = 63.5

Upper quartile = 74

Maximum = 80

Interquartile range = 19

Learn more on Measures of a Data here: brainly.com/question/15097997

#SPJ1

5 0
2 years ago
Someone help real quick
ValentinkaMS [17]

Answer:

Step-by-step explanation:

From the graph <em>f</em>(-2) = 0

g(-2) = -3(-2) + 2

= 6 + 2 = 8.

So f(-2) is less than g(-2).

2. From the graph the y-intercept of f(x) = 8.

To find the y-intercept of g(x) solve y = -3x +2 when x = 0:

y = -3(0) + 2 = 2.

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18/(3/5)=X
X=18*(5/3)
X=30

so at the beginning there were 30 machines

then multiply the percent sold (2/5) by the number at beginning to find the number sold

(2/5)*30=12

so 12 machines were sold

to find the cost per machine divide the total price by number of machines sold so 

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