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Ivahew [28]
3 years ago
14

Find the area of the figure.

Mathematics
1 answer:
kherson [118]3 years ago
5 0

Answer:

area = 164

Step-by-step explanation:

Divide the square into 2 pictures.

; Square 1 = 5×2 = 10

Square 2 = 14×11 (11 from 16-5 )

so, square 2 = 154

all of area = 154+10 = 164

hope it helps ☺️

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What are the coordinates of the circumcenter of a triangle with vertices A(−3, 3) , B(−1, 3) , and C(−1, −1) ?
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Hello Missjay12,

Step 1 :
From the coordinates we have to find the slopes and midpoints of the lines.

Step 2 :
Find the slope of the bisectors and now find the equations of two lines by using slope and one mid points.

Step 3 :
Solve any two pair of equations and find the intersection point.

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so<span> the coordinates of the circumcenter of a triangle with vertices A(−3, 3) , B(−1, 3) , and C(−1, −1)</span> is, -4, 0.



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Help !! Please I can’t find the answer
SVETLANKA909090 [29]

Answer:

\large\boxed{r^2=(x+5)^2+(y-4)^2}

Step-by-step explanation:

The equation of a circle:

(x-h)^2+(y-k)^2=r^2

<em>(h, k)</em><em> - center</em>

<em>r</em><em> - radius</em>

<em />

We have diameter endpoints.

Half the length of the diameter is the length of the radius.

The center of the diameter is the center of the circle.

The formula of a distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Substitute the coordinates of the given points (-8, 2) and (-2, 6):

d=\sqrt{(6-2)^2+(-2-(-8))^2}=\sqrt{4^2+6^2}=\sqrt{16+36}=\sqrt{52}

The radius:

r=\dfrac{d}{2}\to r=\dfrac{\sqrt{52}}{2}

The formula of a midpoint:

\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)

Substitute:

x=\dfrac{-8+(-2)}{2}=\dfrac{-10}{2}=-5\\\\y=\dfrac{2+6}{2}=\dfrac{8}{2}=4

(-5,\ 4)\to h=-5,\ k=4

Finally:

(x-(-5))^2+(y-4)^2=\left(\dfrac{\sqrt{52}}{2}\right)^2\\\\(x+5)^2+(y-4)^2=\dfrac{52}{4}\\\\(x+5)^2+(y-4)^2=13

5 0
3 years ago
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