Answer:
5.5
Step-by-step explanation:
Answer:
2*2 * 2*2 * 2*3
Step-by-step explanation:
96 =16 *6
Break these down, since neither 16 nor 6 are prime
= 4*4 * 2*3
4 in not prime, but 2 and 3 are prime
= 2*2 * 2*2 * 2*3
All of these are prime
Answer:
Area of the rectangular park = 2/3 square mile
Let us assume the width of the rectangular park = x
Then
The length of the rectangular park = 2 2/3 * x mile
= 8x/3 mile
Then
Area of the rectangular park = Length * Width
2/3 = (8x/3) * x
2/3 = 8x^2/3
(2 * 3)/3 = 8x^2
2 = 8x^2
x^2 = 2/8
x^2 = 1/4
x^2 = (1/2)^2
x = 1/2
So the width of the park is 1/2 feet.
Step-by-step explanation:
Brainliest would be nice
Answer:
Lets a,b be elements of G. since G/K is abelian, then there exists k ∈ K such that ab * k = ba (because the class of ab, ![[ab]_K](https://tex.z-dn.net/?f=%20%5Bab%5D_K%20)
is equal to ![[ba]_K](https://tex.z-dn.net/?f=%20%5Bba%5D_K%20)
, thus ab and ba are equal or you can obtain one from the other by multiplying by an element of K.
Since K is a subgroup of H, then k ∈ H. This means that you can obtain ba from ab by multiplying by an element of H, k. Thus, ![[ab]_H = [ba]_H](https://tex.z-dn.net/?f=%20%5Bab%5D_H%20%3D%20%5Bba%5D_H%20)
. Since a and b were generic elements of H, then H/G is abelian.
The answer to this would be complementary angles.
