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kap26 [50]
2 years ago
13

Please help I will give brainliest to whoever answers this question

Mathematics
1 answer:
pantera1 [17]2 years ago
6 0

Hi!

To solve this, we must make an equation in y = mx + b form, where m is the slope and b is the y-intercept.

Since we are looking at a graph with points, it saves us a TON of work, and all we have to do is simply look at the graph. We only need to find m and b, that's it!

M is the slope, and the slope can be represented by the change between points on a line, also known as <em>rise/run. </em>

If we start at point (-4, -1), and go to point (-2, 0), we can see that it goes up 1 and right 2, which would be represented as 1/2.

B is the y-intercept, and that is simply the point that is on the y-axis, which is the point (0, 1), so our number would be 1.

Therefore, plugging these numbers into the equation, our equation is y = <em>1/2</em>x + <em>1</em>

<em></em>

Hope this helps! :D

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The Copy Shop has made 20 copies of a document for you. Since the defective rate is 0.1, you think there may be some defective c
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Answer:

Binomial

There is a 34.87% probability that you will encounter neither of the defective copies among the 10 you examine.

Step-by-step explanation:

For each copy of the document, there are only two possible outcomes. Either it is defective, or it is not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem

Of the 20 copies, 2 are defective, so p = \frac{2}{20} = 0.1.

What is the probability that you will encounter neither of the defective copies among the 10 you examine?

This is P(X = 0) when n = 10.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.1)^{0}.(0.9)^{10} = 0.3487

There is a 34.87% probability that you will encounter neither of the defective copies among the 10 you examine.

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Kindly Only Answer if you know how to do this problem:
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Answer:

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and

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