Find an equation for the line that passes through the points (-6, 3) and (6, -6).

Mathematics

2 answers:

MrRissso [65]1 year ago

7 0

Slope=-9/12 = -3/4

y=mx+b y=-3/4x+b

3=-3/4(-6)+b

b=3+9/2=7.5

Equation is y=-0.75x+7.5

Georgia [21]1 year ago

6 0

Answer:

$y = -\frac{3}{4}x-\frac{3}{2}$

Step-by-step explanation:

First, calculate the slope of the line:

$m = \frac{y_2-y_1}{x_2-x_1}\\m = \frac{(-6) - 3}{6 - (-6)}\\m = \frac{-9}{12}\\m = \frac{-3}{4}$

Next, calculate the y-intercept:

<em>Choose any point on the line</em>.

$(-6,3)$

Solve for $b$ .

$y = mx + b\\b = y - (mx)\\b = 3 - (\frac{-3}{4} * -6)\\b = 3 - \frac{9}{2}\\b = \frac{-3}{2}$

Finally, create the equation:

$y = -\frac{3}{4}x-\frac{3}{2}$

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2 years ago

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Answer:

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