The correct answers are
1. 2c+b-c
2. 31
{\text{Direction of parabola depends on the sign of quadratic coefficient of a }} \hfill \\
{\text{quadratic equation}}. \hfill \\
{\text{For given quadratic equation}}. \hfill \\
a{x^2} + bx + c = 0 \hfill \\
{\text{The parabola is in the upward direction if }}a{\text{ }} > {\text{ }}0{\text{ and in downward direction if }}a < 0 \hfill \\
{\text{Here, the equation of given parabola is }} \hfill \\
{x^2} - 6x + 8 = y \hfill \\
\Rightarrow y = \left( {{x^2} - 6x + 9} \right) - 9 + 8 \hfill \\
\Rightarrow y = {\left( {x - 3} \right)^2} - 1. \hfill \\
{\text{Thus, the parabola is in the upward direction}} \hfill \\
12 is B. You because the graphs slope is 1. 13 is A 7 I think.
First you’d start off by finding the volume of the rectangular prism on the bottom. The formula for this is lwh or (length*width*height) so you’d plug in the numbers and get 4*4*5 which multiplies out to be 80inches cubed. Next you’d have to find the volume of the pyramid by using the formula lwh/3 or ((length*width*height)/3) so it would be ((4*4*6)/3) and that equals 32inches cubed. Finally, you add the 2 volumes together so 80inches cubed+32inches cubed and get 112inches cubed. Hope this helps
Answer:
BC = 1.71
Step-by-step explanation:
well to start we have to know the relationship between angles, legs and the hypotenuse in a right triangle
α = 70°
a: adjacent = BC
h: hypotenuse = 5
sin α = o/h
cos α= a/h
tan α = o/a
we see that it has (angle, adjacent, hypotenuse)
we look at which meets those data between the sine, cosine and tangent
is the cosine
cos α = a/h
Now we replace the values and solve
cos 70 = a/5
0.34202 = a/5
0.34202 * 5 = a
1.7101 = a
round to the neares hundredth
a = 1.7101 = 1.71
BC = 1.71
